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A stone is thrown in a vertically upward direction with a velocity of 5 m/s. If the acceleration of the stone during its motion is 10 m/s^2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?
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A stone is thrown in a vertically upward direction with a velocity of ...
**Height attained by the stone:**
To determine the height attained by the stone, we can use the kinematic equation:
v^2 = u^2 + 2as
where:
v = final velocity (0 m/s at the highest point)
u = initial velocity (5 m/s)
a = acceleration (-10 m/s^2, negative because it is in the downward direction)
s = displacement (height attained by the stone)
By plugging in the given values into the equation, we can solve for s:
0^2 = 5^2 + 2(-10)s
0 = 25 - 20s
20s = 25
s = 25/20
s = 1.25 m
Therefore, the stone will attain a height of 1.25 meters.
**Time taken to reach the height:**
To determine the time taken to reach the height, we can use another kinematic equation:
v = u + at
where:
v = final velocity (0 m/s at the highest point)
u = initial velocity (5 m/s)
a = acceleration (-10 m/s^2, negative because it is in the downward direction)
t = time taken
By plugging in the given values into the equation, we can solve for t:
0 = 5 + (-10)t
-5 = -10t
t = -5/-10
t = 0.5 s
Therefore, it will take 0.5 seconds for the stone to reach the height of 1.25 meters.
In summary, a stone thrown vertically upward with a velocity of 5 m/s and an acceleration of 10 m/s^2 in the downward direction will attain a height of 1.25 meters and it will take 0.5 seconds to reach that height.
To determine the height attained by the stone, we can use the kinematic equation:
v^2 = u^2 + 2as
where:
v = final velocity (0 m/s at the highest point)
u = initial velocity (5 m/s)
a = acceleration (-10 m/s^2, negative because it is in the downward direction)
s = displacement (height attained by the stone)
By plugging in the given values into the equation, we can solve for s:
0^2 = 5^2 + 2(-10)s
0 = 25 - 20s
20s = 25
s = 25/20
s = 1.25 m
Therefore, the stone will attain a height of 1.25 meters.
**Time taken to reach the height:**
To determine the time taken to reach the height, we can use another kinematic equation:
v = u + at
where:
v = final velocity (0 m/s at the highest point)
u = initial velocity (5 m/s)
a = acceleration (-10 m/s^2, negative because it is in the downward direction)
t = time taken
By plugging in the given values into the equation, we can solve for t:
0 = 5 + (-10)t
-5 = -10t
t = -5/-10
t = 0.5 s
Therefore, it will take 0.5 seconds for the stone to reach the height of 1.25 meters.
In summary, a stone thrown vertically upward with a velocity of 5 m/s and an acceleration of 10 m/s^2 in the downward direction will attain a height of 1.25 meters and it will take 0.5 seconds to reach that height.
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A stone is thrown in a vertically upward direction with a velocity of ...
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A stone is thrown in a vertically upward direction with a velocity of 5 m/s. If the acceleration of the stone during its motion is 10 m/s^2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?
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A stone is thrown in a vertically upward direction with a velocity of 5 m/s. If the acceleration of the stone during its motion is 10 m/s^2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A stone is thrown in a vertically upward direction with a velocity of 5 m/s. If the acceleration of the stone during its motion is 10 m/s^2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A stone is thrown in a vertically upward direction with a velocity of 5 m/s. If the acceleration of the stone during its motion is 10 m/s^2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?.
A stone is thrown in a vertically upward direction with a velocity of 5 m/s. If the acceleration of the stone during its motion is 10 m/s^2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A stone is thrown in a vertically upward direction with a velocity of 5 m/s. If the acceleration of the stone during its motion is 10 m/s^2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A stone is thrown in a vertically upward direction with a velocity of 5 m/s. If the acceleration of the stone during its motion is 10 m/s^2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?.
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