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When a ball thrown vertically upwards, it goes through a distance of 19.6 m. Find the initial velocity of the ball and the time taken by it to rise to the highest point? (Acceleration due to gravity, g=9.8 m/s²)?
Most Upvoted Answer
When a ball thrown vertically upwards, it goes through a distance of 1...
Height, s=19.6m
(i) Initial velocity, u=?
Now, when thrown vertically upwards,
Acceleration= −g=−9.8m/s2
Also, at end point, final velocity= 0m/s
⇒v2=u2+2as
So, (0)2=(u)2+2(−9.8)(19.6)
⇒u=19.6m/s
(ii) For going upward,
v=u+at
⇒0=19.6+(−9.8)(t)
⇒t=2s
(i) Initial velocity, u=?
Now, when thrown vertically upwards,
Acceleration= −g=−9.8m/s2
Also, at end point, final velocity= 0m/s
⇒v2=u2+2as
So, (0)2=(u)2+2(−9.8)(19.6)
⇒u=19.6m/s
(ii) For going upward,
v=u+at
⇒0=19.6+(−9.8)(t)
⇒t=2s
Community Answer
When a ball thrown vertically upwards, it goes through a distance of 1...
Given:
Distance travelled by ball, s = 19.6 m
Acceleration due to gravity, g = 9.8 m/s²
Required:
Initial velocity of the ball, u
Time taken by the ball to reach the highest point, t
Solution:
When the ball is thrown vertically upwards, the acceleration acting on it is the acceleration due to gravity, which always acts downward.
Using the equation of motion, s = ut + 1/2 gt², where u is the initial velocity of the ball, t is the time taken by the ball and g is the acceleration due to gravity.
Finding Initial Velocity:
When the ball reaches the highest point, its final velocity becomes zero. Therefore, using the first equation of motion, v = u + gt, we can find the initial velocity of the ball.
At the highest point, v = 0
Therefore, 0 = u - gt
u = gt
Substituting the value of u in the equation of motion, s = ut + 1/2 gt², we get:
s = 1/2 gt²
t = √(2s/g)
Hence, the initial velocity of the ball is u = gt = 9.8 m/s² × √(2s/g) = √(2 × 9.8 m/s² × 19.6 m) = 19.6 m/s.
Finding Time Taken:
The time taken by the ball to reach the highest point is given by t = √(2s/g). Substituting the given values, we get:
t = √(2 × 19.6 m/9.8 m/s²) = √4 = 2 seconds.
Answer:
The initial velocity of the ball is 19.6 m/s and the time taken by the ball to rise to the highest point is 2 seconds.
Distance travelled by ball, s = 19.6 m
Acceleration due to gravity, g = 9.8 m/s²
Required:
Initial velocity of the ball, u
Time taken by the ball to reach the highest point, t
Solution:
When the ball is thrown vertically upwards, the acceleration acting on it is the acceleration due to gravity, which always acts downward.
Using the equation of motion, s = ut + 1/2 gt², where u is the initial velocity of the ball, t is the time taken by the ball and g is the acceleration due to gravity.
Finding Initial Velocity:
When the ball reaches the highest point, its final velocity becomes zero. Therefore, using the first equation of motion, v = u + gt, we can find the initial velocity of the ball.
At the highest point, v = 0
Therefore, 0 = u - gt
u = gt
Substituting the value of u in the equation of motion, s = ut + 1/2 gt², we get:
s = 1/2 gt²
t = √(2s/g)
Hence, the initial velocity of the ball is u = gt = 9.8 m/s² × √(2s/g) = √(2 × 9.8 m/s² × 19.6 m) = 19.6 m/s.
Finding Time Taken:
The time taken by the ball to reach the highest point is given by t = √(2s/g). Substituting the given values, we get:
t = √(2 × 19.6 m/9.8 m/s²) = √4 = 2 seconds.
Answer:
The initial velocity of the ball is 19.6 m/s and the time taken by the ball to rise to the highest point is 2 seconds.
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When a ball thrown vertically upwards, it goes through a distance of 19.6 m. Find the initial velocity of the ball and the time taken by it to rise to the highest point? (Acceleration due to gravity, g=9.8 m/s²)? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about When a ball thrown vertically upwards, it goes through a distance of 19.6 m. Find the initial velocity of the ball and the time taken by it to rise to the highest point? (Acceleration due to gravity, g=9.8 m/s²)? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When a ball thrown vertically upwards, it goes through a distance of 19.6 m. Find the initial velocity of the ball and the time taken by it to rise to the highest point? (Acceleration due to gravity, g=9.8 m/s²)?.
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