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A uniform force of (3 i + j) N acts on a particle of mass 2 kg. Hence the particle is displaced from position (2 i + k) m to position ( 4 i + 3 j - k) m. The work done by the force on the particle is,
  • a)
    9 J
  • b)
    6 J
  • c)
    13 J
  • d)
    15 J
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A uniform force of (3i+j) N acts on a particle of mass 2 kg. Hence the...
Uniform force acting = 3i + j N
Displacement done = (4-2)i + 3j + (-1-1)k
= 2i + 3j -2k
Thus total work done = F.s (dot product here)
We get W = 3 x 2 + 1 x 3 + 0 x -2
= 9J
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Most Upvoted Answer
A uniform force of (3i+j) N acts on a particle of mass 2 kg. Hence the...
Given information:

Force, F = 3i + j N
Mass, m = 2 kg
Initial Position, r1 = 2i + k m
Final Position, r2 = 4i + 3j - k m

To find: Work done by the force on the particle

Formula used: Work done, W = Force x Displacement x cosθ

where,
Force = F
Displacement = r2 - r1
θ = angle between the force and displacement vectors

Calculation:

Displacement vector, d = r2 - r1
= (4i + 3j - k) - (2i + k)
= 2i + 3j - 2k

Force vector, F = 3i + j

θ = angle between F and d

cosθ = (F . d) / (|F| . |d|)
where,
|F| = magnitude of F
|d| = magnitude of d

|F| = √(3² + 1²) = √10
|d| = √(2² + 3² + (-2)²) = √17

F . d = (3i + j) . (2i + 3j - 2k)
= 6 + 3 - 0
= 9

cosθ = (9) / (√10 . √17)
= 9 / √170

Work done, W = F . d . cosθ
= (3i + j) . (2i + 3j - 2k) . (9 / √170)
= 5.29 J (approx)

Therefore, the correct option is (A) 9 J.
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