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On a velocity-time graph, a horizontal straight line corresponds to motion at
  • a)
    constant velocity
  • b)
    zero velocity
  • c)
    increasing velocity
  • d)
    decreasing velocity
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
On a velocity-time graph, a horizontal straight line corresponds to mo...
It is horizontal so, angle is zero and also acceleration is zero. Hence constant velocity.
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Most Upvoted Answer
On a velocity-time graph, a horizontal straight line corresponds to mo...
Your question is wrong a horizontal straight line should correspond to time axis which means it has constant velocity .
please change your question.
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Community Answer
On a velocity-time graph, a horizontal straight line corresponds to mo...
Explanation:

On a velocity-time graph, the velocity is represented on the y-axis and time is represented on the x-axis. A horizontal straight line on this graph indicates that the velocity of the object is constant.


Reasoning:

When the line on the graph is horizontal, it means that the velocity is not changing over time. This implies that the object is moving at a constant speed. In other words, the object is neither accelerating nor decelerating.


Understanding:

In physics, velocity is defined as the rate at which an object changes its position. If an object is moving with a constant velocity, it means that it is moving at the same speed in the same direction without any change. Therefore, on a velocity-time graph, a horizontal line indicates a constant velocity.


Example:

For example, if a car is traveling at a constant speed of 60 km/h for a period of time, the velocity-time graph would show a horizontal line at the height of 60 km/h. This indicates that the car is maintaining a constant velocity of 60 km/h throughout that time period.


Conclusion:

Therefore, on a velocity-time graph, a horizontal straight line corresponds to motion at a constant velocity.
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On a velocity-time graph, a horizontal straight line corresponds to motion ata)constant velocityb)zero velocityc)increasing velocityd)decreasing velocityCorrect answer is option 'A'. Can you explain this answer?
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