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The general integral of the partial differential equation (y + z x) zx — (x + yz)Zy = x2 — y2 is
  • a)
    f(x2 + y2 + z2,xy + z ) = 0 
  • b)
    f(x2 + y2 - z2,x y + z ) = 0 
  • c)
    f(x2 - y2- z2,xy + z) = 0 
  • d)
    f(x2 + y2 + z2,xy - z ) = 0
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
The general integral of the partial differential equation (y + z x) zx...
To find the general integral of the partial differential equation (y z x) zx, we can integrate with respect to both x and z. Let's denote the unknown function as F(x,z):

∂F/∂x = yz + zx

Integrating both sides with respect to x:

F(x,z) = ∫ (yz + zx) dx

= yz*x + 0.5*z*x^2 + g(z)

where g(z) is an arbitrary function of z.

Now, let's differentiate F(x,z) with respect to z:

∂F/∂z = yx + g'(z)

Comparing this with the original partial differential equation, we can see that g'(z) must be equal to 0 for the equation to hold. Therefore, we can conclude that g(z) is a constant, let's call it C.

The general integral of the partial differential equation (y z x) zx is:

F(x,z) = yz*x + 0.5*z*x^2 + C

where C is an arbitrary constant.
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The general integral of the partial differential equation (y + z x) zx...
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