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Which of the following statements regarding ethanoic acid and methyl methanoate are correct?
I. They are functional group isomers with molecular fo nula C2H4O2.
II. They belong to different homologous series.
Ill. They have different chemical properties.
I. They are functional group isomers with molecular fo nula C2H4O2.
II. They belong to different homologous series.
Ill. They have different chemical properties.
- a)1 and II
- b)I, II and III
- c)II and III
- d)I and III
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Which of the following statements regarding ethanoic acid and methyl m...
Methyl methanoate and ethanoic acid are functional group isomers as they have the same molecular formula but the connectivity differs.
Since they have different functional groups, they belong to different homologous series.
Different homologous series have different properties.
Since they have different functional groups, they belong to different homologous series.
Different homologous series have different properties.
Most Upvoted Answer
Which of the following statements regarding ethanoic acid and methyl m...
I. Molecular Formula:
Ethanoic acid and methyl methanoate both have the molecular formula C2H4O2. This means that they both contain two carbon atoms, four hydrogen atoms, and two oxygen atoms. Therefore, Statement I is correct.
II. Homologous Series:
A homologous series is a group of organic compounds that have the same functional group and a similar chemical behavior. Ethanoic acid belongs to the carboxylic acid homologous series, while methyl methanoate belongs to the ester homologous series. These two compounds have different functional groups and therefore belong to different homologous series. Hence, Statement II is correct.
III. Chemical Properties:
Ethanoic acid and methyl methanoate have different chemical properties due to the presence of different functional groups. Ethanoic acid is a carboxylic acid and has acidic properties. It can donate a proton, making it acidic in nature. On the other hand, methyl methanoate is an ester and does not have acidic properties. It does not donate protons and is relatively neutral. Therefore, ethanoic acid and methyl methanoate have different chemical properties. Thus, Statement III is correct.
Conclusion:
Based on the above explanations, we can conclude that Statements I, II, and III are all correct. Therefore, the correct answer is option 'B' - I, II, and III.
Ethanoic acid and methyl methanoate both have the molecular formula C2H4O2. This means that they both contain two carbon atoms, four hydrogen atoms, and two oxygen atoms. Therefore, Statement I is correct.
II. Homologous Series:
A homologous series is a group of organic compounds that have the same functional group and a similar chemical behavior. Ethanoic acid belongs to the carboxylic acid homologous series, while methyl methanoate belongs to the ester homologous series. These two compounds have different functional groups and therefore belong to different homologous series. Hence, Statement II is correct.
III. Chemical Properties:
Ethanoic acid and methyl methanoate have different chemical properties due to the presence of different functional groups. Ethanoic acid is a carboxylic acid and has acidic properties. It can donate a proton, making it acidic in nature. On the other hand, methyl methanoate is an ester and does not have acidic properties. It does not donate protons and is relatively neutral. Therefore, ethanoic acid and methyl methanoate have different chemical properties. Thus, Statement III is correct.
Conclusion:
Based on the above explanations, we can conclude that Statements I, II, and III are all correct. Therefore, the correct answer is option 'B' - I, II, and III.
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Which of the following statements regarding ethanoic acid and methyl methanoate are correct?I. They are functional group isomers with molecular fo nula C2H4O2.II. They belong to different homologous series.Ill. They have different chemical properties.a)1 and IIb)I, II and IIIc)II and IIId)I and IIICorrect answer is option 'B'. Can you explain this answer?
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