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The brakes applied to a car produces a negative acceleration of 10m/s^2.If car takes 5 seconds to stop after applying brakes,calculate distance covered by car before coming to rest.?
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The brakes applied to a car produces a negative acceleration of 10m/s^...
Calculation of Distance Covered by Car before Coming to Rest
Given parameters are:
- Acceleration (a) = -10 m/s^2 (negative because it is a deceleration)
- Time (t) = 5 s
- Initial velocity (u) = 0 m/s (because the car was initially at rest)
- Final velocity (v) = 0 m/s (because the car comes to rest)
Using the Kinematic Equation:
The kinematic equation that relates the distance (s), acceleration (a), initial velocity (u), and time (t) is:
s = ut + (1/2)at^2
Here, u = 0 m/s, a = -10 m/s^2, and t = 5 s. So, substituting these values in the above equation, we get:
s = 0 + (1/2)(-10)(5)^2
s = -125 m
Explanation:
The negative sign in the answer indicates that the car traveled in the opposite direction of its initial velocity. The magnitude of the distance covered is 125 meters before coming to rest. This means that the car traveled a considerable distance before it was brought to a stop.
The negative acceleration of 10 m/s^2 means that the car's velocity decreased by 10 m/s every second. It took 5 seconds for the car's velocity to decrease from its initial velocity of 0 m/s to 0 m/s. During this time, the car covered a distance of 125 meters.
Therefore, the car traveled 125 meters before coming to rest.
Given parameters are:
- Acceleration (a) = -10 m/s^2 (negative because it is a deceleration)
- Time (t) = 5 s
- Initial velocity (u) = 0 m/s (because the car was initially at rest)
- Final velocity (v) = 0 m/s (because the car comes to rest)
Using the Kinematic Equation:
The kinematic equation that relates the distance (s), acceleration (a), initial velocity (u), and time (t) is:
s = ut + (1/2)at^2
Here, u = 0 m/s, a = -10 m/s^2, and t = 5 s. So, substituting these values in the above equation, we get:
s = 0 + (1/2)(-10)(5)^2
s = -125 m
Explanation:
The negative sign in the answer indicates that the car traveled in the opposite direction of its initial velocity. The magnitude of the distance covered is 125 meters before coming to rest. This means that the car traveled a considerable distance before it was brought to a stop.
The negative acceleration of 10 m/s^2 means that the car's velocity decreased by 10 m/s every second. It took 5 seconds for the car's velocity to decrease from its initial velocity of 0 m/s to 0 m/s. During this time, the car covered a distance of 125 meters.
Therefore, the car traveled 125 meters before coming to rest.
Community Answer
The brakes applied to a car produces a negative acceleration of 10m/s^...
Here final velocity v=0, hence the total distance travelled will be S = - 1 2 a t 2 . Here a=-10 m/s2 and time t=5 s.. So the distance travelled is S = - 1 2 × - 10× 5 2 = 125 m.
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The brakes applied to a car produces a negative acceleration of 10m/s^2.If car takes 5 seconds to stop after applying brakes,calculate distance covered by car before coming to rest.?
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The brakes applied to a car produces a negative acceleration of 10m/s^2.If car takes 5 seconds to stop after applying brakes,calculate distance covered by car before coming to rest.? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about The brakes applied to a car produces a negative acceleration of 10m/s^2.If car takes 5 seconds to stop after applying brakes,calculate distance covered by car before coming to rest.? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The brakes applied to a car produces a negative acceleration of 10m/s^2.If car takes 5 seconds to stop after applying brakes,calculate distance covered by car before coming to rest.?.
The brakes applied to a car produces a negative acceleration of 10m/s^2.If car takes 5 seconds to stop after applying brakes,calculate distance covered by car before coming to rest.? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about The brakes applied to a car produces a negative acceleration of 10m/s^2.If car takes 5 seconds to stop after applying brakes,calculate distance covered by car before coming to rest.? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The brakes applied to a car produces a negative acceleration of 10m/s^2.If car takes 5 seconds to stop after applying brakes,calculate distance covered by car before coming to rest.?.
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