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A cycle started from rest and within 10s it divelops velocity to 10m/s and then by applying brakes velocity is reduced to 5m/s in 5s
find the acceleration in both cases
find the distance travelled in both cases?
find the acceleration in both cases
find the distance travelled in both cases?
Most Upvoted Answer
A cycle started from rest and within 10s it divelops velocity to 10m/s...
Acceleration During Acceleration Phase
- Initial Velocity (u): 0 m/s (started from rest)
- Final Velocity (v): 10 m/s
- Time (t): 10 s
- Formula for Acceleration (a):
a = (v - u) / t
- Calculation:
a = (10 m/s - 0 m/s) / 10 s = 1 m/s²
Distance Travelled During Acceleration Phase
- Formula for Distance (s):
s = ut + (1/2)at²
- Calculation:
s = 0 + (1/2)(1 m/s²)(10 s)² = 50 m
Acceleration During Braking Phase
- Initial Velocity (u): 10 m/s
- Final Velocity (v): 5 m/s
- Time (t): 5 s
- Formula for Acceleration (a):
a = (v - u) / t
- Calculation:
a = (5 m/s - 10 m/s) / 5 s = -1 m/s² (deceleration)
Distance Travelled During Braking Phase
- Formula for Distance (s):
s = ut + (1/2)at²
- Calculation:
s = (10 m/s)(5 s) + (1/2)(-1 m/s²)(5 s)²
= 50 m - 12.5 m = 37.5 m
Summary
- Acceleration Phase:
- Acceleration = 1 m/s²
- Distance = 50 m
- Braking Phase:
- Acceleration = -1 m/s²
- Distance = 37.5 m
This analysis provides a clear understanding of the motion of the cycle during both acceleration and braking phases.
- Initial Velocity (u): 0 m/s (started from rest)
- Final Velocity (v): 10 m/s
- Time (t): 10 s
- Formula for Acceleration (a):
a = (v - u) / t
- Calculation:
a = (10 m/s - 0 m/s) / 10 s = 1 m/s²
Distance Travelled During Acceleration Phase
- Formula for Distance (s):
s = ut + (1/2)at²
- Calculation:
s = 0 + (1/2)(1 m/s²)(10 s)² = 50 m
Acceleration During Braking Phase
- Initial Velocity (u): 10 m/s
- Final Velocity (v): 5 m/s
- Time (t): 5 s
- Formula for Acceleration (a):
a = (v - u) / t
- Calculation:
a = (5 m/s - 10 m/s) / 5 s = -1 m/s² (deceleration)
Distance Travelled During Braking Phase
- Formula for Distance (s):
s = ut + (1/2)at²
- Calculation:
s = (10 m/s)(5 s) + (1/2)(-1 m/s²)(5 s)²
= 50 m - 12.5 m = 37.5 m
Summary
- Acceleration Phase:
- Acceleration = 1 m/s²
- Distance = 50 m
- Braking Phase:
- Acceleration = -1 m/s²
- Distance = 37.5 m
This analysis provides a clear understanding of the motion of the cycle during both acceleration and braking phases.
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A cycle started from rest and within 10s it divelops velocity to 10m/s and then by applying brakes velocity is reduced to 5m/s in 5s find the acceleration in both casesfind the distance travelled in both cases?
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A cycle started from rest and within 10s it divelops velocity to 10m/s and then by applying brakes velocity is reduced to 5m/s in 5s find the acceleration in both casesfind the distance travelled in both cases? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A cycle started from rest and within 10s it divelops velocity to 10m/s and then by applying brakes velocity is reduced to 5m/s in 5s find the acceleration in both casesfind the distance travelled in both cases? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A cycle started from rest and within 10s it divelops velocity to 10m/s and then by applying brakes velocity is reduced to 5m/s in 5s find the acceleration in both casesfind the distance travelled in both cases?.
A cycle started from rest and within 10s it divelops velocity to 10m/s and then by applying brakes velocity is reduced to 5m/s in 5s find the acceleration in both casesfind the distance travelled in both cases? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A cycle started from rest and within 10s it divelops velocity to 10m/s and then by applying brakes velocity is reduced to 5m/s in 5s find the acceleration in both casesfind the distance travelled in both cases? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A cycle started from rest and within 10s it divelops velocity to 10m/s and then by applying brakes velocity is reduced to 5m/s in 5s find the acceleration in both casesfind the distance travelled in both cases?.
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