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A body of mass 2kg is at rest at the origin of a frame of reference. A force of 5N acts on it at t= 0. The force acts for 4s and then stops. a) What is the acceleration produced by the force on the body. b) What is the velocity at t = 4s c) Draw the v-t graph for the period t=0 to t= 6s d) Find the distance travelled in 6s.?
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A body of mass 2kg is at rest at the origin of a frame of reference. A...
Solution:
a) Acceleration produced by the force on the body can be calculated using the formula:
F = ma
where F is the force applied, m is the mass of the object and a is the acceleration produced.
Given, F = 5N and m = 2kg
So, a = F/m = 5/2 = 2.5 m/s^2
Therefore, the acceleration produced by the force on the body is 2.5 m/s^2.
b) Velocity at t = 4s can be calculated using the formula:
v = u + at
where u is the initial velocity, a is the acceleration and t is the time taken.
As the body is initially at rest, u = 0.
Given, a = 2.5 m/s^2 and t = 4s
So, v = 0 + (2.5 x 4) = 10 m/s
Therefore, the velocity at t = 4s is 10 m/s.
c) The v-t graph for the period t=0 to t=6s can be drawn as follows:
At t = 0, the velocity is 0.
From t = 0 to t = 4s, the body experiences a constant acceleration of 2.5 m/s^2. So, the velocity increases linearly from 0 to 10 m/s.
From t = 4s to t = 6s, the body moves with a constant velocity of 10 m/s. So, the graph is a straight line parallel to the time axis.
d) Distance travelled in 6s can be calculated using the formula:
s = ut + (1/2)at^2
where u is the initial velocity, a is the acceleration and t is the time taken.
From t = 0 to t = 4s, the body experiences a constant acceleration of 2.5 m/s^2. So, the initial velocity is 0.
So, distance travelled from t = 0 to t = 4s is:
s1 = 0 + (1/2) x 2.5 x (4)^2 = 20m
From t = 4s to t = 6s, the body moves with a constant velocity of 10 m/s.
So, distance travelled from t = 4s to t = 6s is:
s2 = 10 x 2 = 20m
Therefore, the total distance travelled in 6s is:
s = s1 + s2 = 20 + 20 = 40m
Hence, the distance travelled in 6s is 40m.
a) Acceleration produced by the force on the body can be calculated using the formula:
F = ma
where F is the force applied, m is the mass of the object and a is the acceleration produced.
Given, F = 5N and m = 2kg
So, a = F/m = 5/2 = 2.5 m/s^2
Therefore, the acceleration produced by the force on the body is 2.5 m/s^2.
b) Velocity at t = 4s can be calculated using the formula:
v = u + at
where u is the initial velocity, a is the acceleration and t is the time taken.
As the body is initially at rest, u = 0.
Given, a = 2.5 m/s^2 and t = 4s
So, v = 0 + (2.5 x 4) = 10 m/s
Therefore, the velocity at t = 4s is 10 m/s.
c) The v-t graph for the period t=0 to t=6s can be drawn as follows:
At t = 0, the velocity is 0.
From t = 0 to t = 4s, the body experiences a constant acceleration of 2.5 m/s^2. So, the velocity increases linearly from 0 to 10 m/s.
From t = 4s to t = 6s, the body moves with a constant velocity of 10 m/s. So, the graph is a straight line parallel to the time axis.
d) Distance travelled in 6s can be calculated using the formula:
s = ut + (1/2)at^2
where u is the initial velocity, a is the acceleration and t is the time taken.
From t = 0 to t = 4s, the body experiences a constant acceleration of 2.5 m/s^2. So, the initial velocity is 0.
So, distance travelled from t = 0 to t = 4s is:
s1 = 0 + (1/2) x 2.5 x (4)^2 = 20m
From t = 4s to t = 6s, the body moves with a constant velocity of 10 m/s.
So, distance travelled from t = 4s to t = 6s is:
s2 = 10 x 2 = 20m
Therefore, the total distance travelled in 6s is:
s = s1 + s2 = 20 + 20 = 40m
Hence, the distance travelled in 6s is 40m.
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A body of mass 2kg is at rest at the origin of a frame of reference. A...
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A body of mass 2kg is at rest at the origin of a frame of reference. A force of 5N acts on it at t= 0. The force acts for 4s and then stops. a) What is the acceleration produced by the force on the body. b) What is the velocity at t = 4s c) Draw the v-t graph for the period t=0 to t= 6s d) Find the distance travelled in 6s.?
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A body of mass 2kg is at rest at the origin of a frame of reference. A force of 5N acts on it at t= 0. The force acts for 4s and then stops. a) What is the acceleration produced by the force on the body. b) What is the velocity at t = 4s c) Draw the v-t graph for the period t=0 to t= 6s d) Find the distance travelled in 6s.? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A body of mass 2kg is at rest at the origin of a frame of reference. A force of 5N acts on it at t= 0. The force acts for 4s and then stops. a) What is the acceleration produced by the force on the body. b) What is the velocity at t = 4s c) Draw the v-t graph for the period t=0 to t= 6s d) Find the distance travelled in 6s.? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body of mass 2kg is at rest at the origin of a frame of reference. A force of 5N acts on it at t= 0. The force acts for 4s and then stops. a) What is the acceleration produced by the force on the body. b) What is the velocity at t = 4s c) Draw the v-t graph for the period t=0 to t= 6s d) Find the distance travelled in 6s.?.
A body of mass 2kg is at rest at the origin of a frame of reference. A force of 5N acts on it at t= 0. The force acts for 4s and then stops. a) What is the acceleration produced by the force on the body. b) What is the velocity at t = 4s c) Draw the v-t graph for the period t=0 to t= 6s d) Find the distance travelled in 6s.? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A body of mass 2kg is at rest at the origin of a frame of reference. A force of 5N acts on it at t= 0. The force acts for 4s and then stops. a) What is the acceleration produced by the force on the body. b) What is the velocity at t = 4s c) Draw the v-t graph for the period t=0 to t= 6s d) Find the distance travelled in 6s.? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body of mass 2kg is at rest at the origin of a frame of reference. A force of 5N acts on it at t= 0. The force acts for 4s and then stops. a) What is the acceleration produced by the force on the body. b) What is the velocity at t = 4s c) Draw the v-t graph for the period t=0 to t= 6s d) Find the distance travelled in 6s.?.
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