A block OF mass 50 kg can slide on a rough horizontal surface. the coe...
Force required to set it in motion= limiting frictionlimiting friction = coefficient of friction × Normal rxn =0.6× 500 = 300 ans
A block OF mass 50 kg can slide on a rough horizontal surface. the coe...
Understanding the Problem
To determine the least force of pull required to make a block slide on a rough surface, we must consider the frictional force acting against the motion.
Given Data
- Mass of the block (m): 50 kg
- Coefficient of friction (μ): 0.6
Calculating the Normal Force
The normal force (N) is equal to the weight of the block. This can be calculated as:
- N = m * g
- g (acceleration due to gravity) is approximately 9.81 m/s²
So,
- N = 50 kg * 9.81 m/s² = 490.5 N
Determining the Frictional Force
The frictional force (f) that opposes the motion can be calculated using the formula:
- f = μ * N
Substituting the values:
- f = 0.6 * 490.5 N = 294.3 N
Calculating the Least Force of Pull
To just overcome the friction and start sliding the block, the applied force (F) must equal the frictional force. Therefore, the least force of pull required is:
- F = f = 294.3 N
Conclusion
The least force of pull that will cause the block to just slide is approximately 294.3 N. This force must be applied horizontally to overcome the frictional resistance between the block and the rough surface.