if (X+y=5) $(xy=6)then find value of (x3 -y3)

Question

if  (X+y=5) $(xy=6)then find value of (x3 -y3)

Answer

actually if X=2 and Y=3 thn it is -19 and if X=3 and Y=2 thn it is 19

Answer

if u put X=2 and Y=3 then its answer is -3 or if u put X=3 and Y=2 then its answer is 3

Answer

no .....no.... if u put X=2 and Y=3 thn its answer is -10 or if u pit X=3 and Y=2 thn its answer is 10

Answer

plz solve using identity

Answer

The given problem states that if the equations X + y = 5 and Xy = 6 are true, we need to find the value of (X^3 - y^3). Let's solve this problem step by step.

Step 1: Solve the equations X + y = 5 and Xy = 6 to find the values of X and y.
To solve these equations, we can use the method of substitution or elimination. Let's use the method of substitution.

From the first equation, we can express X in terms of y:
X = 5 - y

Substituting this value of X in the second equation, we get:
(5 - y)y = 6

Simplifying this equation, we have:
5y - y^2 = 6
Rearranging the terms, we get:
y^2 - 5y + 6 = 0

Factoring this quadratic equation, we have:
(y - 2)(y - 3) = 0

This gives two possible values for y: y = 2 or y = 3.

Step 2: Substitute the values of y back into the equation X = 5 - y to find the corresponding values of X.
For y = 2:
X = 5 - 2
X = 3

For y = 3:
X = 5 - 3
X = 2

So, the possible values for X are X = 3 or X = 2.

Step 3: Calculate the value of (X^3 - y^3) using the obtained values of X and y.

For X = 3 and y = 2:
(X^3 - y^3) = (3^3 - 2^3)
(X^3 - y^3) = (27 - 8)
(X^3 - y^3) = 19

For X = 2 and y = 3:
(X^3 - y^3) = (2^3 - 3^3)
(X^3 - y^3) = (8 - 27)
(X^3 - y^3) = -19

Therefore, the value of (X^3 - y^3) can be either 19 or -19, depending on the values of X and y.

In summary, by solving the given equations and substituting the values of X and y into the expression (X^3 - y^3), we found that the value of (X^3 - y^3) can be either 19 or -19.

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