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A person crossing a road with a certain velocity due north, sees a car moving towards east. The relative velocity of the car with respect to the person is root 2 times that of the person. The angle made by the relative velocity with the East is?
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A person crossing a road with a certain velocity due north, sees a car...
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A person crossing a road with a certain velocity due north, sees a car...
Analysis:

Let's assume that the person is moving with a velocity of Vp due north and the car is moving with a velocity of Vc towards the east. We need to find the angle made by the relative velocity of the car with respect to the person with the east direction.

Relative Velocity:

The relative velocity of the car with respect to the person can be calculated by subtracting the velocity of the person from the velocity of the car.

Relative Velocity (Vr) = Vc - Vp

Magnitude of Relative Velocity:

Given that the magnitude of the relative velocity of the car with respect to the person is √2 times the magnitude of the person's velocity.

|Vr| = √2 * |Vp|

Since the person is moving due north, the magnitude of the person's velocity is equal to the magnitude of the relative velocity.

|Vr| = |Vp|

Therefore, we can write the equation as:

|Vp| = √2 * |Vp|

Squaring both sides of the equation, we get:

|Vp|^2 = 2 * |Vp|^2

Simplifying the equation, we get:

|Vp|^2 = 0

This implies that the magnitude of the person's velocity is zero. However, since we know that the person is moving, this is not possible.

Therefore, there is no solution to this problem.
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A person crossing a road with a certain velocity due north, sees a car moving towards east. The relative velocity of the car with respect to the person is root 2 times that of the person. The angle made by the relative velocity with the East is?
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