Two coins are tossed simultaneously. Then, the probability of getting ...
Understanding the Problem
When two coins are tossed simultaneously, we want to find the probability of getting at most one head. "At most one head" means we can have either zero heads or one head.
Possible Outcomes
When tossing two coins, the possible outcomes are:
- HH (two heads)
- HT (one head, one tail)
- TH (one head, one tail)
- TT (two tails)
So, the complete sample space is: {HH, HT, TH, TT}, which consists of 4 outcomes.
Favorable Outcomes
Now, let's identify the outcomes where we have at most one head:
- 0 Heads: TT
- 1 Head: HT, TH
Thus, the favorable outcomes for at most one head are: {TT, HT, TH}. This gives us a total of 3 favorable outcomes.
Calculating Probability
Probability is calculated using the formula:
Probability = (Number of Favorable Outcomes) / (Total Number of Outcomes)
Here, we have:
- Number of Favorable Outcomes = 3 (TT, HT, TH)
- Total Number of Outcomes = 4 (HH, HT, TH, TT)
So, the probability of getting at most one head is:
Probability = 3 / 4
Conclusion
Therefore, the probability of getting at most one head when two coins are tossed is:
3/4
Thus, the correct answer is option 'B'.
Two coins are tossed simultaneously. Then, the probability of getting ...
I think the ans is c
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