The north pole of a long horizontal bar magnet is being brought closer to a vertical conducting plane, along the perpendicular direction. The induced current in the conducting plane isa)Clockwiseb)Anticlockwisec)Horizonatald)VerticalCorrect answer is option 'B'. Can you explain this answer?

Explore Courses UPSC Exam UPSC Test Series Free Notes EduRev Infinity

Open App

JEE Exam > JEE Questions > The north pole of a long horizontal bar magne...

Join the Discussion on the App

The north pole of a long horizontal bar magnet is being brought closer to a vertical conducting plane, along the perpendicular direction. The induced current in the conducting plane is

a)
Clockwise
b)
Anticlockwise
c)
Horizonatal
d)
Vertical

Correct answer is option 'B'. Can you explain this answer?

FREE This question is part of

BITSAT Physics Test - 4

Attempt Test

Attempt this Test

Verified Answer

The north pole of a long horizontal bar magnet is being brought closer...

As per Lenz's law, induced current must be anticlockwise, so as to develop north polarity to oppose the incoming north pole.

View all questions of this test

View all answers Start learning for free

< Previous Question Next Question >

Explore Courses for JEE exam

Similar JEE Doubts

A 10 cm long perfectly conducting wire PQ is moving with a velocity 1 cm/s on a pair of horizontal rails of zero resistance. One side of the rails is connected to an inductor L = 1 mH and a resistance R = 1Ω as shown in the figure. The horizontal rails, L and R lie in the same plane with a uniform magnetic field B = 1 T perpendicular to the plane. If the key S is closed at certain instant, the current in the circuit after 1 millisecond is x *10-3 A, where the value of x is ________[Assume the velocity of wire PQ remains constant (1 cm/s) after key S is closed. Given: e-1 = 0.37, where eis base of the natural logarithm] Correct answer is '0.63'. Can you explain this answer?

View answer

A 10 cm long perfectly conducting wire PQ is moving, with a velocity 1cm/s on a pair of horizontal rails of zero resistance. One side of the rails is connected to an inductor L = 1 mH and a resistance R = 1Ω as shown in figure. The horizontal rails, L and R lie in the same plane with a uniform magnetic field B = 1 T perpendicular to the plane. If the key S is closed at certain instant, the current in the circuit after 1 millisecond is x × 10–3A, where the value of x is_______.[Assume the velocity of wire PQ remains constant (1 cm/s) after key S is closed.Given: e–1 = 0.37, where e is base of the natural logarithm] Correct answer is '0.63'. Can you explain this answer?

View answer

A conducting square loop of side L and resistance R moves in its plane with a uniform velocity v perpendicular to one of its sides. A magnetic induction B, constant in time and space, pointing perpendicular and into the plane of the loop exists everywhere.The current induced in the loop is

View answer

A circular disc of mass m and radius R is set into motion on a horizontal floor with a linear speed v in the forward direction and an angular speed omega=v/3R in clockwise direction. Find the magnitude of the total angular momentum of the disc about the axis perpendicular to the plane of disc and passing through the bottom most point 'O' of the disc and fixed to the ground.

View answer

A conducting bar of length L is free to slide on two parallel conducting rails as shown in the figure.Two resistors R1 and R2 are connected across the ends of the rails. There is a uniform magnetic field pointing into the page. An external agent pulls the bar to the left at a constant speed v.The correct statement about the directions of induced currents I1 and I2 flowing through R1 and R2 respectively is

View answer

Top Courses for JEEView all

Physics for JEE Main & Advanced

Mock Tests for JEE Main and Advanced 2025

Chemistry for JEE Main & Advanced

Mathematics (Maths) for JEE Main & Advanced

Chapter-wise Tests for JEE Main & Advanced

Top Courses for JEE

View all

The north pole of a long horizontal bar magnet is being brought closer to a vertical conducting plane, along the perpendicular direction. The induced current in the conducting plane isa)Clockwiseb)Anticlockwisec)Horizonatald)VerticalCorrect answer is option 'B'. Can you explain this answer?

Share with a Friend

Answer this doubt

Question Description
The north pole of a long horizontal bar magnet is being brought closer to a vertical conducting plane, along the perpendicular direction. The induced current in the conducting plane isa)Clockwiseb)Anticlockwisec)Horizonatald)VerticalCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The north pole of a long horizontal bar magnet is being brought closer to a vertical conducting plane, along the perpendicular direction. The induced current in the conducting plane isa)Clockwiseb)Anticlockwisec)Horizonatald)VerticalCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The north pole of a long horizontal bar magnet is being brought closer to a vertical conducting plane, along the perpendicular direction. The induced current in the conducting plane isa)Clockwiseb)Anticlockwisec)Horizonatald)VerticalCorrect answer is option 'B'. Can you explain this answer?.

Solutions for The north pole of a long horizontal bar magnet is being brought closer to a vertical conducting plane, along the perpendicular direction. The induced current in the conducting plane isa)Clockwiseb)Anticlockwisec)Horizonatald)VerticalCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of The north pole of a long horizontal bar magnet is being brought closer to a vertical conducting plane, along the perpendicular direction. The induced current in the conducting plane isa)Clockwiseb)Anticlockwisec)Horizonatald)VerticalCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The north pole of a long horizontal bar magnet is being brought closer to a vertical conducting plane, along the perpendicular direction. The induced current in the conducting plane isa)Clockwiseb)Anticlockwisec)Horizonatald)VerticalCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for The north pole of a long horizontal bar magnet is being brought closer to a vertical conducting plane, along the perpendicular direction. The induced current in the conducting plane isa)Clockwiseb)Anticlockwisec)Horizonatald)VerticalCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of The north pole of a long horizontal bar magnet is being brought closer to a vertical conducting plane, along the perpendicular direction. The induced current in the conducting plane isa)Clockwiseb)Anticlockwisec)Horizonatald)VerticalCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The north pole of a long horizontal bar magnet is being brought closer to a vertical conducting plane, along the perpendicular direction. The induced current in the conducting plane isa)Clockwiseb)Anticlockwisec)Horizonatald)VerticalCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice JEE tests.

Explore Courses for JEE exam