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The jaws of a vernier callipers touch the inner wall of calorimeter without any undue pressure. The position of zero of vernier scale on the main scale reads 3.48. The 6th of vernier scale division is coinciding with any main scale division. Vernier constant of callipers is 0.01 cm. Find actual internal diameter of calorimeter, when it is observed that the vernier scale has a zero error of – 0.03 cm.
  • a)
    3.37 cm
  • b)
    3.57 cm
  • c)
    3.42 cm
  • d)
    3.54 cm
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The jaws of a vernier callipers touch the inner wall of calorimeter wi...
Main scale reading = 3.48 cm
LC = 0.01 cm
Vernier coincidence = 6
Reading
= Main scale reading + Vernier coincidence × LC
= 3.48 + 6 × 0.01
= 3.48 + 0.06
= 3.54 cm
Corrected reading
= reading – zero error
= 3.54 – (-0.03)
= 3.54 + 0.03
3.57 cm
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Most Upvoted Answer
The jaws of a vernier callipers touch the inner wall of calorimeter wi...
We can use the formula:

Actual reading = Main scale reading + Vernier scale reading x Vernier constant

Let's first calculate the Vernier scale reading when there is zero error:

Since the 6th division of Vernier scale coincides with a main scale division, the Vernier scale reading is 0.06 cm.

Now, let's find the Main scale reading:

The position of zero of Vernier scale on the main scale reads 3.48. This means that the 48th division of the main scale coincides with the zero of the Vernier scale. Therefore, the Main scale reading is 3.48 cm.

Using the formula above, we can calculate the actual internal diameter of the calorimeter:

Actual reading = 3.48 cm + 0.06 cm x 0.01 cm
Actual reading = 3.48 cm + 0.0006 cm
Actual reading = 3.4806 cm

Therefore, the actual internal diameter of the calorimeter is 3.4806 cm.
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Community Answer
The jaws of a vernier callipers touch the inner wall of calorimeter wi...
3.57
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The jaws of a vernier callipers touch the inner wall of calorimeter without any undue pressure. The position of zero of vernier scale on the main scale reads 3.48. The 6th of vernier scale division is coinciding with any main scale division. Vernier constant of callipers is 0.01 cm. Find actual internal diameter of calorimeter, when it is observed that the vernier scale has a zero error of – 0.03 cm.a)3.37 cmb)3.57 cmc)3.42 cmd)3.54 cmCorrect answer is option 'B'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The jaws of a vernier callipers touch the inner wall of calorimeter without any undue pressure. The position of zero of vernier scale on the main scale reads 3.48. The 6th of vernier scale division is coinciding with any main scale division. Vernier constant of callipers is 0.01 cm. Find actual internal diameter of calorimeter, when it is observed that the vernier scale has a zero error of – 0.03 cm.a)3.37 cmb)3.57 cmc)3.42 cmd)3.54 cmCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The jaws of a vernier callipers touch the inner wall of calorimeter without any undue pressure. The position of zero of vernier scale on the main scale reads 3.48. The 6th of vernier scale division is coinciding with any main scale division. Vernier constant of callipers is 0.01 cm. Find actual internal diameter of calorimeter, when it is observed that the vernier scale has a zero error of – 0.03 cm.a)3.37 cmb)3.57 cmc)3.42 cmd)3.54 cmCorrect answer is option 'B'. Can you explain this answer?.
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