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There are two Vernier calipers both of which have 1 cm divided into 10 equal divisions on the main scale. The Vernier scale of one of the calipers (C1) has 10 equal divisions that correspond to 9 main scale divisions. The Vernier scale of the other caliper (C2) has 10 equal divisions that correspond to 11 main scale divisions. The readings of the two calipers are shown in the figure. The measured values (in cm) by calipers C1 and C2, respectively, are:
  • a)
    2.87 and 2.86
  • b)
    2.85 and 2.82
  • c)
    2.87 and 2.87
  • d)
    2.87 and 2.83
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
There are two Vernier calipers both of which have1 cm divided into 10 ...
MSD = 1/10 cm = 0.1 cm
For first vernier caliper,
10 VSD = 9 MSD
⇒ VSD = 9/10 MSD = 0.9 × 0.1 = 0.09 cm
Reading
= main scale reading upto coinciding main scale division − n × VSD
= 3.5 – 7 × 0.09 = 3.5 – 0.63 = 2.87 cm
For second vernier caliper,
10 VSD = 11 MSD
⇒ VSD = 11/10 MSD = 1.1 × 0.1 = 0.11 cm
Reading = 3.6 – 7 × 0.11 = 3.6 – 0.77 = 2.83 cm
Why we not used the formula here that we were using in previous problems,
Here is the formula we were using,
Least count = MSD – VSD
Reading = Main Scale Reading + Vernier coincidence × Least Count
We derived these formula for Vernier callipers having n divisions of the Vernier scale equal to n-1 divisions of the main scale.
If we apply these formula on first vernier caliper then we will get the same result, but if we apply these formula on the second vernier caliper then we will get negative least count (0.1 − 0.11 = −0.01cm), which is not possible, that is why we cannot apply these formula in this case. 
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Most Upvoted Answer
There are two Vernier calipers both of which have1 cm divided into 10 ...
MSD = 1/10 cm = 0.1 cm
For first vernier caliper,
10 VSD = 9 MSD
⇒ VSD = 9/10 MSD = 0.9 × 0.1 = 0.09 cm
Reading
= main scale reading upto coinciding main scale division − n × VSD
= 3.5 – 7 × 0.09 = 3.5 – 0.63 = 2.87 cm
For second vernier caliper,
10 VSD = 11 MSD
⇒ VSD = 11/10 MSD = 1.1 × 0.1 = 0.11 cm
Reading = 3.6 – 7 × 0.11 = 3.6 – 0.77 = 2.83 cm
Why we not used the formula here that we were using in previous problems,
Here is the formula we were using,
Least count = MSD – VSD
Reading = Main Scale Reading + Vernier coincidence × Least Count
We derived these formula for Vernier callipers having n divisions of the Vernier scale equal to n-1 divisions of the main scale.
If we apply these formula on first vernier caliper then we will get the same result, but if we apply these formula on the second vernier caliper then we will get negative least count (0.1 − 0.11 = −0.01cm), which is not possible, that is why we cannot apply these formula in this case. 
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There are two Vernier calipers both of which have1 cm divided into 10 equal divisions on the main scale.The Vernier scale of one of the calipers(C1) has 10 equal divisions that correspond to 9 main scale divisions.The Vernier scale of the other caliper(C2) has 10 equal divisions that correspond to 11 main scale divisions.The readings of the two calipers are shown in the figure. The measured values (in cm) by calipers C1 and C2, respectively, are:a)2.87 and 2.86b)2.85 and 2.82c)2.87 and 2.87d)2.87 and 2.83Correct answer is option 'D'. Can you explain this answer?
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There are two Vernier calipers both of which have1 cm divided into 10 equal divisions on the main scale.The Vernier scale of one of the calipers(C1) has 10 equal divisions that correspond to 9 main scale divisions.The Vernier scale of the other caliper(C2) has 10 equal divisions that correspond to 11 main scale divisions.The readings of the two calipers are shown in the figure. The measured values (in cm) by calipers C1 and C2, respectively, are:a)2.87 and 2.86b)2.85 and 2.82c)2.87 and 2.87d)2.87 and 2.83Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about There are two Vernier calipers both of which have1 cm divided into 10 equal divisions on the main scale.The Vernier scale of one of the calipers(C1) has 10 equal divisions that correspond to 9 main scale divisions.The Vernier scale of the other caliper(C2) has 10 equal divisions that correspond to 11 main scale divisions.The readings of the two calipers are shown in the figure. The measured values (in cm) by calipers C1 and C2, respectively, are:a)2.87 and 2.86b)2.85 and 2.82c)2.87 and 2.87d)2.87 and 2.83Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for There are two Vernier calipers both of which have1 cm divided into 10 equal divisions on the main scale.The Vernier scale of one of the calipers(C1) has 10 equal divisions that correspond to 9 main scale divisions.The Vernier scale of the other caliper(C2) has 10 equal divisions that correspond to 11 main scale divisions.The readings of the two calipers are shown in the figure. The measured values (in cm) by calipers C1 and C2, respectively, are:a)2.87 and 2.86b)2.85 and 2.82c)2.87 and 2.87d)2.87 and 2.83Correct answer is option 'D'. Can you explain this answer?.
Solutions for There are two Vernier calipers both of which have1 cm divided into 10 equal divisions on the main scale.The Vernier scale of one of the calipers(C1) has 10 equal divisions that correspond to 9 main scale divisions.The Vernier scale of the other caliper(C2) has 10 equal divisions that correspond to 11 main scale divisions.The readings of the two calipers are shown in the figure. The measured values (in cm) by calipers C1 and C2, respectively, are:a)2.87 and 2.86b)2.85 and 2.82c)2.87 and 2.87d)2.87 and 2.83Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
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