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A horizontal fixed beam AB of span 6 m has uniform flexural rigidity of 4200 kN m2. During loading, the support B sinks downwards by 25 mm. The moment induced at the end A is
  • a)
    105 kN m (Anticlockwise)
  • b)
    17.5 kN m (Clockwise)
  • c)
    17.5 kN m (Anticlockwise)
  • d)
    105 kN m (Clockwise)
Correct answer is option 'C'. Can you explain this answer?
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A horizontal fixed beam ABof span 6 m has uniform flexural rigidity of...
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A horizontal fixed beam ABof span 6 m has uniform flexural rigidity of...
Given:
- Span of the beam (AB) = 6 m
- Flexural rigidity (EI) = 4200 kN m2
- Displacement of support B (δB) = 25 mm

To find:
- Moment induced at the end A

Assumptions:
- The beam is initially horizontal and straight.
- The beam is loaded uniformly.
- The beam is considered to be prismatic (constant cross-section).

Solution:
Step 1: Calculate the slope at support B
- The slope at support B (θB) can be calculated using the formula: θB = δB / L
- Here, δB = 25 mm = 0.025 m (given)
- L = Span of the beam = 6 m (given)
- θB = 0.025 / 6

Step 2: Calculate the moment at support B
- The moment at support B (MB) can be calculated using the formula: MB = (θB * EI) / L
- Here, EI = 4200 kN m2 (given)
- MB = (0.025 / 6) * 4200 / 6

Step 3: Calculate the moment at end A
- The moment at end A (MA) can be calculated using the formula: MA = MB * (L - a) / L
- Here, a = 0 (since the moment is measured at the end A)
- MA = MB * (L - a) / L = MB

Hence, the moment induced at the end A is 17.5 kN m (anticlockwise), which is option 'C'.
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A horizontal fixed beam ABof span 6 m has uniform flexural rigidity of 4200 kN m2. During loading, the support B sinks downwards by 25 mm. The moment induced at the end A isa)105 kN m (Anticlockwise)b)17.5 kN m (Clockwise)c)17.5 kN m (Anticlockwise)d)105 kN m (Clockwise)Correct answer is option 'C'. Can you explain this answer?
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A horizontal fixed beam ABof span 6 m has uniform flexural rigidity of 4200 kN m2. During loading, the support B sinks downwards by 25 mm. The moment induced at the end A isa)105 kN m (Anticlockwise)b)17.5 kN m (Clockwise)c)17.5 kN m (Anticlockwise)d)105 kN m (Clockwise)Correct answer is option 'C'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A horizontal fixed beam ABof span 6 m has uniform flexural rigidity of 4200 kN m2. During loading, the support B sinks downwards by 25 mm. The moment induced at the end A isa)105 kN m (Anticlockwise)b)17.5 kN m (Clockwise)c)17.5 kN m (Anticlockwise)d)105 kN m (Clockwise)Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A horizontal fixed beam ABof span 6 m has uniform flexural rigidity of 4200 kN m2. During loading, the support B sinks downwards by 25 mm. The moment induced at the end A isa)105 kN m (Anticlockwise)b)17.5 kN m (Clockwise)c)17.5 kN m (Anticlockwise)d)105 kN m (Clockwise)Correct answer is option 'C'. Can you explain this answer?.
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