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A uniform electric field pointing in positive x-direction exists in a region. Let A be the origin, B be the point on the x-axis at x=+1 cm and C be the point on the y-axis at y=+1 cm. Then the potentials at the points A,B and C satisfy
- a)VA> VB
- b)VA< VC
- c)VA> VC
- d)VA< VB
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A uniform electric field pointing in positive x-direction exists in a ...
Since the electric field is uniform and pointing in the positive x-direction, the potential difference between any two points along the x-axis is given by ΔV = -Edx, where dx is the distance between the two points. Therefore, the potential difference between points A and B is ΔVAB = -E(1 cm) = -E.
Similarly, the potential difference between points A and C is ΔVAC = -Edy, where dy is the distance between the two points. Since the electric field is pointing in the positive x-direction and C is on the y-axis, the potential difference between A and C is zero, i.e. ΔVAC = 0.
Using the principle of superposition, we can find the potential at point B with respect to point A as follows:
VB - VA = ΔVAB
VB = VA + ΔVAB
VB = 0 - E
Therefore, the potentials at points A, B, and C satisfy:
VA = 0
VB = -E
VC = 0
Similarly, the potential difference between points A and C is ΔVAC = -Edy, where dy is the distance between the two points. Since the electric field is pointing in the positive x-direction and C is on the y-axis, the potential difference between A and C is zero, i.e. ΔVAC = 0.
Using the principle of superposition, we can find the potential at point B with respect to point A as follows:
VB - VA = ΔVAB
VB = VA + ΔVAB
VB = 0 - E
Therefore, the potentials at points A, B, and C satisfy:
VA = 0
VB = -E
VC = 0
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A uniform electric field pointing in positive x-direction exists in a region. Let A be the origin, B be the point on the x-axis at x=+1 cm and C be the point on the y-axis at y=+1 cm. Then the potentials at the points A,B and C satisfya)VA> VBb)VA< VCc)VA> VCd)VA< VBCorrect answer is option 'A'. Can you explain this answer?
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