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The state of an ideal gas is changed from (T1, P1) to (T2, P2) in a constant volume process. To calculate the change in enthalpy (Δh) ail of the following properties/variables are required.
- a)Cv,P1, P2
- b)Cp, T1, T2
- c)Cp, T1, T2, P1, P2
- d)Cv, P1 P2, T1, T2
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The state of an ideal gas is changed from (T1, P1) to (T2, P2) in a co...
Calculation of Change in Enthalpy (Δh) in Constant Volume Process- Properties/Variables Required:
- Cp (specific heat at constant pressure)
- Initial temperature (T1)
- Final temperature (T2)
- In a constant volume process, the enthalpy change (Δh) is equal to the heat added to the system. The formula for calculating the change in enthalpy is Δh = Cp * (T2 - T1).
- Cp is the specific heat at constant pressure, which represents the amount of heat required to raise the temperature of one unit mass of a substance by one degree Celsius at constant pressure.
- We need the initial temperature (T1) and final temperature (T2) to calculate the change in enthalpy, as the enthalpy change is directly proportional to the temperature change.
- Therefore, the properties/variables required to calculate the change in enthalpy (Δh) in a constant volume process are Cp, T1, and T2.
Most Upvoted Answer
The state of an ideal gas is changed from (T1, P1) to (T2, P2) in a co...
ΔH) we can use the formula:
ΔH = Cp * ΔT
Where Cp is the specific heat at constant pressure and ΔT is the change in temperature.
Since the process is constant volume, the work done is zero and therefore ΔU = q, where ΔU is the change in internal energy and q is the heat transferred.
Using the first law of thermodynamics, we have:
ΔU = q - w
Since w = 0, we have:
ΔU = q
Also, since the process is ideal gas at constant volume, we have:
ΔU = Cv * ΔT
Where Cv is the specific heat at constant volume.
Combining the above equations, we get:
Cv * ΔT = Cp * ΔT - ΔH
Rearranging, we get:
ΔH = Cp * ΔT - Cv * ΔT
Substituting the values for Cp and Cv for an ideal gas (Cp = Cv + R), we get:
ΔH = (Cv + R) * ΔT - Cv * ΔT
Simplifying, we get:
ΔH = R * ΔT
Therefore, the change in enthalpy for an ideal gas undergoing a constant volume process is directly proportional to the change in temperature, and is given by the product of the gas constant and the change in temperature.
ΔH = Cp * ΔT
Where Cp is the specific heat at constant pressure and ΔT is the change in temperature.
Since the process is constant volume, the work done is zero and therefore ΔU = q, where ΔU is the change in internal energy and q is the heat transferred.
Using the first law of thermodynamics, we have:
ΔU = q - w
Since w = 0, we have:
ΔU = q
Also, since the process is ideal gas at constant volume, we have:
ΔU = Cv * ΔT
Where Cv is the specific heat at constant volume.
Combining the above equations, we get:
Cv * ΔT = Cp * ΔT - ΔH
Rearranging, we get:
ΔH = Cp * ΔT - Cv * ΔT
Substituting the values for Cp and Cv for an ideal gas (Cp = Cv + R), we get:
ΔH = (Cv + R) * ΔT - Cv * ΔT
Simplifying, we get:
ΔH = R * ΔT
Therefore, the change in enthalpy for an ideal gas undergoing a constant volume process is directly proportional to the change in temperature, and is given by the product of the gas constant and the change in temperature.
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The state of an ideal gas is changed from (T1, P1) to (T2, P2) in a constant volume process. To calculate the change in enthalpy (Δh) ail of the following properties/variables are required.a)Cv,P1, P2b)Cp, T1, T2c)Cp, T1, T2, P1, P2d)Cv, P1 P2, T1,T2Correct answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2025 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about The state of an ideal gas is changed from (T1, P1) to (T2, P2) in a constant volume process. To calculate the change in enthalpy (Δh) ail of the following properties/variables are required.a)Cv,P1, P2b)Cp, T1, T2c)Cp, T1, T2, P1, P2d)Cv, P1 P2, T1,T2Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The state of an ideal gas is changed from (T1, P1) to (T2, P2) in a constant volume process. To calculate the change in enthalpy (Δh) ail of the following properties/variables are required.a)Cv,P1, P2b)Cp, T1, T2c)Cp, T1, T2, P1, P2d)Cv, P1 P2, T1,T2Correct answer is option 'B'. Can you explain this answer?.
The state of an ideal gas is changed from (T1, P1) to (T2, P2) in a constant volume process. To calculate the change in enthalpy (Δh) ail of the following properties/variables are required.a)Cv,P1, P2b)Cp, T1, T2c)Cp, T1, T2, P1, P2d)Cv, P1 P2, T1,T2Correct answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2025 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about The state of an ideal gas is changed from (T1, P1) to (T2, P2) in a constant volume process. To calculate the change in enthalpy (Δh) ail of the following properties/variables are required.a)Cv,P1, P2b)Cp, T1, T2c)Cp, T1, T2, P1, P2d)Cv, P1 P2, T1,T2Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The state of an ideal gas is changed from (T1, P1) to (T2, P2) in a constant volume process. To calculate the change in enthalpy (Δh) ail of the following properties/variables are required.a)Cv,P1, P2b)Cp, T1, T2c)Cp, T1, T2, P1, P2d)Cv, P1 P2, T1,T2Correct answer is option 'B'. Can you explain this answer?.
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