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The number of integral values of  ‘a’ so that the point of local minima of f(x) = x3 – 3ax2 + 3(a2 – 1)x + 1 is less than 4 and point of local maximum is greater than −2, is/are  
    Correct answer is '3'. Can you explain this answer?
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    The number of integral values of ‘a’ so that the point of ...
    f'(x) = 3(x2− 2ax + a2 −1)
    f'(x) = 0 ⇒   (x − a)2 = 1, x = a + 1, a – 1
    −2<a − 1, a + 1 < 4
    ⇒ −1<a , a < 3  
    ⇒ a ∈ (−1, 3)
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    The number of integral values of ‘a’ so that the point of local minima of f(x) = x3 – 3ax2 + 3(a2 – 1)x + 1 is less than 4 and point of local maximum is greater than −2, is/are Correct answer is '3'. Can you explain this answer?
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    The number of integral values of ‘a’ so that the point of local minima of f(x) = x3 – 3ax2 + 3(a2 – 1)x + 1 is less than 4 and point of local maximum is greater than −2, is/are Correct answer is '3'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The number of integral values of ‘a’ so that the point of local minima of f(x) = x3 – 3ax2 + 3(a2 – 1)x + 1 is less than 4 and point of local maximum is greater than −2, is/are Correct answer is '3'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The number of integral values of ‘a’ so that the point of local minima of f(x) = x3 – 3ax2 + 3(a2 – 1)x + 1 is less than 4 and point of local maximum is greater than −2, is/are Correct answer is '3'. Can you explain this answer?.
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