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If 3x+2 - 9-1/ x> 0 , then the interval of x can be
  • a)
    x ∈ (0,∞)
  • b)
    x ∈ (-5, 5)
  • c)
    x ∈ R
  • d)
    x ∈ (-∞, 0)
Correct answer is option 'A'. Can you explain this answer?
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If 3x+2 - 9-1/ x 0 , then the interval of x can bea)x (0,)b)x (-5, 5...
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If 3x+2 - 9-1/ x 0 , then the interval of x can bea)x (0,)b)x (-5, 5...
Explanation:

Given Equation:
3x + 2 - 9 - 1/x > 0

Simplify the Equation:
3x - 7 - 1/x > 0
3x - 1/x > 7

Find the Critical Points:
To find the critical points, set the expression equal to 0:
3x - 1/x = 7
3x^2 - 7x - 1 = 0
Using the quadratic formula, we find the roots of the equation:
x = (7 ± √(49 + 12))/6
x = (7 ± √61)/6

Interval Analysis:
Since the inequality is greater than 0, we need to find where the expression is positive.
This occurs when x is greater than the larger root or less than the smaller root:
x > (7 + √61)/6 or x < (7="" -="" />

Final Interval:
Therefore, the interval of x where the given inequality holds true is:
x > (7 + √61)/6, which can be written as x > (7 + √61)/6
Therefore, the correct option is (A) x > (7 + √61)/6.
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If 3x+2 - 9-1/ x 0 , then the interval of x can bea)x (0,)b)x (-5, 5)c)x Rd)x (-, 0)Correct answer is option 'A'. Can you explain this answer?
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