The number of arrangements of the letters in the word `FAILURE’, so th...
Explanation:
To solve this problem, we need to consider the vowels as a single letter. So, the word `FAILURE’ can be considered as `FLR’ and the vowels `AUE’ can be considered as `V’. Now, we have to find the number of arrangements of the letters `FLRV’ such that the vowels always come together.
Steps:
To find the number of arrangements of the letters `FLRV’ such that the vowels always come together, we need to follow these steps:
1. Consider the group of vowels `V’ as a single letter.
2. Now, we have 4 letters `F’, `L’, `R’ and `V’. The number of arrangements of these 4 letters is 4! = 24.
3. But, the group `V’ can be arranged in 3! ways within itself. So, we need to subtract those arrangements from the total number of arrangements.
4. Therefore, the number of arrangements of the letters `FLRV’ such that the vowels always come together is 4! - 3! = 24 - 6 = 18.
Answer:
The number of arrangements of the letters in the word `FAILURE’, so that vowels are always coming together is option
(d) none of these. Because the correct answer is 18, which is not given in any of the options.