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The sum of all 4 digit number containing the digits 2, 4, 6, 8, without repetitions is a) 1,33,330 b) 1,22,220 c) 2,13,330 d) 1,33,320?
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The sum of all 4 digit number containing the digits 2, 4, 6, 8, withou...
Problem: Find the sum of all 4 digit number containing the digits 2, 4, 6, 8, without repetitions.

Solution:
To find the sum of all 4 digit numbers containing the digits 2, 4, 6, 8, we need to first find the total number of such numbers and then add them up.

Step 1: Finding the Total Number of 4 Digit Numbers
We need to find the total number of 4 digit numbers that can be formed using the digits 2, 4, 6, 8, without repetitions. This can be done using the permutation formula, which is:

nPr = n! / (n - r)!

Where n is the total number of objects and r is the number of objects taken at a time.

In this case, n = 4 (since we have 4 digits) and r = 4 (since we need to form 4 digit numbers). Therefore, the total number of 4 digit numbers that can be formed is:

4P4 = 4! / (4 - 4)! = 4! / 0! = 24

Step 2: Finding the Sum of All 4 Digit Numbers
Now that we know the total number of 4 digit numbers that can be formed, we can find their sum by adding up all the possible numbers.

Since each digit appears in each place value (thousands, hundreds, tens, and units) the same number of times, we can find the sum of each place value separately and then add them up.

Thousands Place:
The total sum of the thousands place can be found by adding up all the possible numbers that can be formed using the digits 2, 4, 6, 8 in the thousands place, and then multiplying it by the total number of such numbers (which is 6, as there are 6 permutations of the remaining 3 digits).

2 + 4 + 6 + 8 = 20
20 x 6 = 120

Hundreds Place:
The same logic can be applied to the hundreds place, which gives us:

2 + 4 + 6 + 8 = 20
20 x 6 = 120

Tens Place:
Similarly, for the tens place, we have:

2 + 4 + 6 + 8 = 20
20 x 6 = 120

Units Place:
Finally, for the units place, we can again use the same logic, which gives us:

2 + 4 + 6 + 8 = 20
20 x 6 = 120

Total Sum:
Now that we have the sum of each place value, we can add them up to get the total sum:

120 + 120 + 120 + 120 = 480

Therefore, the sum of all 4 digit numbers containing the digits 2, 4, 6, 8, without repetitions is 480.

Answer: Option d) 1,33,320.
Community Answer
The sum of all 4 digit number containing the digits 2, 4, 6, 8, withou...
Answer will be 133320.
Since During addition,
In every place we will get
"adding of 2,4,6 & 8, Six times each."
So 6(2+4+6+8)=120.
And
120
120
120
120
133320
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The sum of all 4 digit number containing the digits 2, 4, 6, 8, without repetitions is a) 1,33,330 b) 1,22,220 c) 2,13,330 d) 1,33,320?
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