Class 12 Exam > Class 12 Questions > Peroxide ion (O22-)(i) has five completely fi...
Start Learning for Free
Peroxide ion (O22-)
(i) has five completely filled antibonding molecular orbitals
(ii) is diamagnetic
(iii) has bond order one
(iv) is isoelectronic with neon
Which of these are correct ?
(i) has five completely filled antibonding molecular orbitals
(ii) is diamagnetic
(iii) has bond order one
(iv) is isoelectronic with neon
Which of these are correct ?
- a)III and IV
- b)I, II & IV
- c)II and III
- d)I and IV
Correct answer is option 'C'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
Peroxide ion (O22-)(i) has five completely filled antibonding molecula...
Peroxide ion is diamagnetic as it doesn't contain any unpaired electrons and it's bond order is one as the number of bonding electrons are 10 and anti-bonding electrons are 8...therefore bond order will be (10-8)/2 =1...the correct option is C
Free Test
FREE
| Start Free Test |
Community Answer
Peroxide ion (O22-)(i) has five completely filled antibonding molecula...
And IVc)II and IIId)I and IIIe)II, III and IV
The correct answer is a) III and IV.
Explanation:
(i) Peroxide ion (O22-) has one antibonding molecular orbital, not five.
(ii) Diamagnetism or paramagnetism depends on the presence of unpaired electrons. Peroxide ion has all its electrons paired, so it is diamagnetic.
(iii) Bond order is calculated as (number of bonding electrons - number of antibonding electrons)/2. Peroxide ion has 12 bonding electrons and 6 antibonding electrons, so its bond order is (12-6)/2 = 3.
(iv) Isoelectronic species have the same number of electrons. Neon has 10 electrons, and peroxide ion also has 10 electrons (8 from oxygen atoms and 2 from the charge). Therefore, they are isoelectronic.
The correct answer is a) III and IV.
Explanation:
(i) Peroxide ion (O22-) has one antibonding molecular orbital, not five.
(ii) Diamagnetism or paramagnetism depends on the presence of unpaired electrons. Peroxide ion has all its electrons paired, so it is diamagnetic.
(iii) Bond order is calculated as (number of bonding electrons - number of antibonding electrons)/2. Peroxide ion has 12 bonding electrons and 6 antibonding electrons, so its bond order is (12-6)/2 = 3.
(iv) Isoelectronic species have the same number of electrons. Neon has 10 electrons, and peroxide ion also has 10 electrons (8 from oxygen atoms and 2 from the charge). Therefore, they are isoelectronic.
|
Explore Courses for Class 12 exam
|
|
Similar Class 12 Doubts
Peroxide ion (O22-)(i) has five completely filled antibonding molecular orbitals(ii) is diamagnetic(iii) has bond order one(iv) is isoelectronic with neonWhich of these are correct ?a)III and IVb)I, II & IVc)II and IIId)I and IVCorrect answer is option 'C'. Can you explain this answer?
Question Description
Peroxide ion (O22-)(i) has five completely filled antibonding molecular orbitals(ii) is diamagnetic(iii) has bond order one(iv) is isoelectronic with neonWhich of these are correct ?a)III and IVb)I, II & IVc)II and IIId)I and IVCorrect answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Peroxide ion (O22-)(i) has five completely filled antibonding molecular orbitals(ii) is diamagnetic(iii) has bond order one(iv) is isoelectronic with neonWhich of these are correct ?a)III and IVb)I, II & IVc)II and IIId)I and IVCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Peroxide ion (O22-)(i) has five completely filled antibonding molecular orbitals(ii) is diamagnetic(iii) has bond order one(iv) is isoelectronic with neonWhich of these are correct ?a)III and IVb)I, II & IVc)II and IIId)I and IVCorrect answer is option 'C'. Can you explain this answer?.
Peroxide ion (O22-)(i) has five completely filled antibonding molecular orbitals(ii) is diamagnetic(iii) has bond order one(iv) is isoelectronic with neonWhich of these are correct ?a)III and IVb)I, II & IVc)II and IIId)I and IVCorrect answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Peroxide ion (O22-)(i) has five completely filled antibonding molecular orbitals(ii) is diamagnetic(iii) has bond order one(iv) is isoelectronic with neonWhich of these are correct ?a)III and IVb)I, II & IVc)II and IIId)I and IVCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Peroxide ion (O22-)(i) has five completely filled antibonding molecular orbitals(ii) is diamagnetic(iii) has bond order one(iv) is isoelectronic with neonWhich of these are correct ?a)III and IVb)I, II & IVc)II and IIId)I and IVCorrect answer is option 'C'. Can you explain this answer?.
Solutions for Peroxide ion (O22-)(i) has five completely filled antibonding molecular orbitals(ii) is diamagnetic(iii) has bond order one(iv) is isoelectronic with neonWhich of these are correct ?a)III and IVb)I, II & IVc)II and IIId)I and IVCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
Here you can find the meaning of Peroxide ion (O22-)(i) has five completely filled antibonding molecular orbitals(ii) is diamagnetic(iii) has bond order one(iv) is isoelectronic with neonWhich of these are correct ?a)III and IVb)I, II & IVc)II and IIId)I and IVCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Peroxide ion (O22-)(i) has five completely filled antibonding molecular orbitals(ii) is diamagnetic(iii) has bond order one(iv) is isoelectronic with neonWhich of these are correct ?a)III and IVb)I, II & IVc)II and IIId)I and IVCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for Peroxide ion (O22-)(i) has five completely filled antibonding molecular orbitals(ii) is diamagnetic(iii) has bond order one(iv) is isoelectronic with neonWhich of these are correct ?a)III and IVb)I, II & IVc)II and IIId)I and IVCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of Peroxide ion (O22-)(i) has five completely filled antibonding molecular orbitals(ii) is diamagnetic(iii) has bond order one(iv) is isoelectronic with neonWhich of these are correct ?a)III and IVb)I, II & IVc)II and IIId)I and IVCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Peroxide ion (O22-)(i) has five completely filled antibonding molecular orbitals(ii) is diamagnetic(iii) has bond order one(iv) is isoelectronic with neonWhich of these are correct ?a)III and IVb)I, II & IVc)II and IIId)I and IVCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice Class 12 tests.
|
|
Explore Courses for Class 12 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup