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When crystals of CuSO4 . 4NH3 are dissolved in water, there is hardly any evidence for the presence of Cu2+ ions or ammonia molecules. A new ion [Cu(NH3)4]2+ is furnished in which ammonia molecules are directly linked with the metal ion. Similarly, aqueous solution of Fe(CN)2 .4KCNdoes not give tests of Fe2+ and CN-ions but give test for new ion [Fe(CN)6]4-called ferrocyanide ion.Q.The hybridisation, geometry and magnetic property of [Fe(CN)6]4- area)d2sp3, octahedral, diamagnetib)d2sp3, octahedral, paramagneticc)sp3d2, octahedral, diamagneticd)sp3d2, octahedral, paramagneticCorrect answer is option 'A'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about When crystals of CuSO4 . 4NH3 are dissolved in water, there is hardly any evidence for the presence of Cu2+ ions or ammonia molecules. A new ion [Cu(NH3)4]2+ is furnished in which ammonia molecules are directly linked with the metal ion. Similarly, aqueous solution of Fe(CN)2 .4KCNdoes not give tests of Fe2+ and CN-ions but give test for new ion [Fe(CN)6]4-called ferrocyanide ion.Q.The hybridisation, geometry and magnetic property of [Fe(CN)6]4- area)d2sp3, octahedral, diamagnetib)d2sp3, octahedral, paramagneticc)sp3d2, octahedral, diamagneticd)sp3d2, octahedral, paramagneticCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When crystals of CuSO4 . 4NH3 are dissolved in water, there is hardly any evidence for the presence of Cu2+ ions or ammonia molecules. A new ion [Cu(NH3)4]2+ is furnished in which ammonia molecules are directly linked with the metal ion. Similarly, aqueous solution of Fe(CN)2 .4KCNdoes not give tests of Fe2+ and CN-ions but give test for new ion [Fe(CN)6]4-called ferrocyanide ion.Q.The hybridisation, geometry and magnetic property of [Fe(CN)6]4- area)d2sp3, octahedral, diamagnetib)d2sp3, octahedral, paramagneticc)sp3d2, octahedral, diamagneticd)sp3d2, octahedral, paramagneticCorrect answer is option 'A'. Can you explain this answer?.

Solutions for When crystals of CuSO4 . 4NH3 are dissolved in water, there is hardly any evidence for the presence of Cu2+ ions or ammonia molecules. A new ion [Cu(NH3)4]2+ is furnished in which ammonia molecules are directly linked with the metal ion. Similarly, aqueous solution of Fe(CN)2 .4KCNdoes not give tests of Fe2+ and CN-ions but give test for new ion [Fe(CN)6]4-called ferrocyanide ion.Q.The hybridisation, geometry and magnetic property of [Fe(CN)6]4- area)d2sp3, octahedral, diamagnetib)d2sp3, octahedral, paramagneticc)sp3d2, octahedral, diamagneticd)sp3d2, octahedral, paramagneticCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12. Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.

Here you can find the meaning of When crystals of CuSO4 . 4NH3 are dissolved in water, there is hardly any evidence for the presence of Cu2+ ions or ammonia molecules. A new ion [Cu(NH3)4]2+ is furnished in which ammonia molecules are directly linked with the metal ion. Similarly, aqueous solution of Fe(CN)2 .4KCNdoes not give tests of Fe2+ and CN-ions but give test for new ion [Fe(CN)6]4-called ferrocyanide ion.Q.The hybridisation, geometry and magnetic property of [Fe(CN)6]4- area)d2sp3, octahedral, diamagnetib)d2sp3, octahedral, paramagneticc)sp3d2, octahedral, diamagneticd)sp3d2, octahedral, paramagneticCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of When crystals of CuSO4 . 4NH3 are dissolved in water, there is hardly any evidence for the presence of Cu2+ ions or ammonia molecules. A new ion [Cu(NH3)4]2+ is furnished in which ammonia molecules are directly linked with the metal ion. Similarly, aqueous solution of Fe(CN)2 .4KCNdoes not give tests of Fe2+ and CN-ions but give test for new ion [Fe(CN)6]4-called ferrocyanide ion.Q.The hybridisation, geometry and magnetic property of [Fe(CN)6]4- area)d2sp3, octahedral, diamagnetib)d2sp3, octahedral, paramagneticc)sp3d2, octahedral, diamagneticd)sp3d2, octahedral, paramagneticCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for When crystals of CuSO4 . 4NH3 are dissolved in water, there is hardly any evidence for the presence of Cu2+ ions or ammonia molecules. A new ion [Cu(NH3)4]2+ is furnished in which ammonia molecules are directly linked with the metal ion. Similarly, aqueous solution of Fe(CN)2 .4KCNdoes not give tests of Fe2+ and CN-ions but give test for new ion [Fe(CN)6]4-called ferrocyanide ion.Q.The hybridisation, geometry and magnetic property of [Fe(CN)6]4- area)d2sp3, octahedral, diamagnetib)d2sp3, octahedral, paramagneticc)sp3d2, octahedral, diamagneticd)sp3d2, octahedral, paramagneticCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of When crystals of CuSO4 . 4NH3 are dissolved in water, there is hardly any evidence for the presence of Cu2+ ions or ammonia molecules. A new ion [Cu(NH3)4]2+ is furnished in which ammonia molecules are directly linked with the metal ion. Similarly, aqueous solution of Fe(CN)2 .4KCNdoes not give tests of Fe2+ and CN-ions but give test for new ion [Fe(CN)6]4-called ferrocyanide ion.Q.The hybridisation, geometry and magnetic property of [Fe(CN)6]4- area)d2sp3, octahedral, diamagnetib)d2sp3, octahedral, paramagneticc)sp3d2, octahedral, diamagneticd)sp3d2, octahedral, paramagneticCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice When crystals of CuSO4 . 4NH3 are dissolved in water, there is hardly any evidence for the presence of Cu2+ ions or ammonia molecules. A new ion [Cu(NH3)4]2+ is furnished in which ammonia molecules are directly linked with the metal ion. Similarly, aqueous solution of Fe(CN)2 .4KCNdoes not give tests of Fe2+ and CN-ions but give test for new ion [Fe(CN)6]4-called ferrocyanide ion.Q.The hybridisation, geometry and magnetic property of [Fe(CN)6]4- area)d2sp3, octahedral, diamagnetib)d2sp3, octahedral, paramagneticc)sp3d2, octahedral, diamagneticd)sp3d2, octahedral, paramagneticCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice Class 12 tests.