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When crystals of CuSO4 . 4NH3 are dissolved in water, there is hardly any evidence for the presence of Cu2+ ions or ammonia molecules. A new ion [Cu(NH3)4]2+ is furnished in which ammonia molecules are directly linked with the metal ion. Similarly, aqueous solution of Fe(CN)2 .4KCNdoes not give tests of Fe2+ and CN- ions but give test for new ion [Fe(CN)6]4- called ferrocyanide ion.
Q.
The hybridisation, geometry and magnetic property of [Fe(CN)6]4- are
- a)d2sp3, octahedral, diamagneti
- b)d2sp3, octahedral, paramagnetic
- c)sp3d2, octahedral, diamagnetic
- d)sp3d2, octahedral, paramagnetic
Correct answer is option 'A'. Can you explain this answer?
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When crystals of CuSO4 . 4NH3 are dissolved in water, there is hardly ...
It is inner orbital complex, diamagnetic.
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When crystals of CuSO4 . 4NH3 are dissolved in water, there is hardly ...
Hybridisation, Geometry and Magnetic Property of [Fe(CN)6]4-
Hybridisation:
The central metal ion Fe2+ has 6 ligands around it which include 6 cyanide ions (CN-) in [Fe(CN)6]4-. The hybridisation of the metal ion depends on the number of ligands and the type of ligands present around it. In this case, the hybridisation of Fe2+ ion in [Fe(CN)6]4- is dsp2.
Geometry:
The geometry of the complex ion is octahedral. The six ligands occupy the vertices of an octahedron and the metal ion occupies the center.
Magnetic Property:
The magnetic property of a complex ion depends on the number of unpaired electrons in the metal ion. In this case, Fe2+ ion has four unpaired electrons. Due to the presence of unpaired electrons, [Fe(CN)6]4- is paramagnetic in nature.
Therefore, the correct option is (a) d2sp3, octahedral, diamagnetic.
Hybridisation:
The central metal ion Fe2+ has 6 ligands around it which include 6 cyanide ions (CN-) in [Fe(CN)6]4-. The hybridisation of the metal ion depends on the number of ligands and the type of ligands present around it. In this case, the hybridisation of Fe2+ ion in [Fe(CN)6]4- is dsp2.
Geometry:
The geometry of the complex ion is octahedral. The six ligands occupy the vertices of an octahedron and the metal ion occupies the center.
Magnetic Property:
The magnetic property of a complex ion depends on the number of unpaired electrons in the metal ion. In this case, Fe2+ ion has four unpaired electrons. Due to the presence of unpaired electrons, [Fe(CN)6]4- is paramagnetic in nature.
Therefore, the correct option is (a) d2sp3, octahedral, diamagnetic.
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When crystals of CuSO4 . 4NH3 are dissolved in water, there is hardly any evidence for the presence of Cu2+ ions or ammonia molecules. A new ion [Cu(NH3)4]2+ is furnished in which ammonia molecules are directly linked with the metal ion. Similarly, aqueous solution of Fe(CN)2 .4KCNdoes not give tests of Fe2+ and CN-ions but give test for new ion [Fe(CN)6]4-called ferrocyanide ion.Q.The hybridisation, geometry and magnetic property of [Fe(CN)6]4- area)d2sp3, octahedral, diamagnetib)d2sp3, octahedral, paramagneticc)sp3d2, octahedral, diamagneticd)sp3d2, octahedral, paramagneticCorrect answer is option 'A'. Can you explain this answer?
Question Description
When crystals of CuSO4 . 4NH3 are dissolved in water, there is hardly any evidence for the presence of Cu2+ ions or ammonia molecules. A new ion [Cu(NH3)4]2+ is furnished in which ammonia molecules are directly linked with the metal ion. Similarly, aqueous solution of Fe(CN)2 .4KCNdoes not give tests of Fe2+ and CN-ions but give test for new ion [Fe(CN)6]4-called ferrocyanide ion.Q.The hybridisation, geometry and magnetic property of [Fe(CN)6]4- area)d2sp3, octahedral, diamagnetib)d2sp3, octahedral, paramagneticc)sp3d2, octahedral, diamagneticd)sp3d2, octahedral, paramagneticCorrect answer is option 'A'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about When crystals of CuSO4 . 4NH3 are dissolved in water, there is hardly any evidence for the presence of Cu2+ ions or ammonia molecules. A new ion [Cu(NH3)4]2+ is furnished in which ammonia molecules are directly linked with the metal ion. Similarly, aqueous solution of Fe(CN)2 .4KCNdoes not give tests of Fe2+ and CN-ions but give test for new ion [Fe(CN)6]4-called ferrocyanide ion.Q.The hybridisation, geometry and magnetic property of [Fe(CN)6]4- area)d2sp3, octahedral, diamagnetib)d2sp3, octahedral, paramagneticc)sp3d2, octahedral, diamagneticd)sp3d2, octahedral, paramagneticCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When crystals of CuSO4 . 4NH3 are dissolved in water, there is hardly any evidence for the presence of Cu2+ ions or ammonia molecules. A new ion [Cu(NH3)4]2+ is furnished in which ammonia molecules are directly linked with the metal ion. Similarly, aqueous solution of Fe(CN)2 .4KCNdoes not give tests of Fe2+ and CN-ions but give test for new ion [Fe(CN)6]4-called ferrocyanide ion.Q.The hybridisation, geometry and magnetic property of [Fe(CN)6]4- area)d2sp3, octahedral, diamagnetib)d2sp3, octahedral, paramagneticc)sp3d2, octahedral, diamagneticd)sp3d2, octahedral, paramagneticCorrect answer is option 'A'. Can you explain this answer?.
When crystals of CuSO4 . 4NH3 are dissolved in water, there is hardly any evidence for the presence of Cu2+ ions or ammonia molecules. A new ion [Cu(NH3)4]2+ is furnished in which ammonia molecules are directly linked with the metal ion. Similarly, aqueous solution of Fe(CN)2 .4KCNdoes not give tests of Fe2+ and CN-ions but give test for new ion [Fe(CN)6]4-called ferrocyanide ion.Q.The hybridisation, geometry and magnetic property of [Fe(CN)6]4- area)d2sp3, octahedral, diamagnetib)d2sp3, octahedral, paramagneticc)sp3d2, octahedral, diamagneticd)sp3d2, octahedral, paramagneticCorrect answer is option 'A'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about When crystals of CuSO4 . 4NH3 are dissolved in water, there is hardly any evidence for the presence of Cu2+ ions or ammonia molecules. A new ion [Cu(NH3)4]2+ is furnished in which ammonia molecules are directly linked with the metal ion. Similarly, aqueous solution of Fe(CN)2 .4KCNdoes not give tests of Fe2+ and CN-ions but give test for new ion [Fe(CN)6]4-called ferrocyanide ion.Q.The hybridisation, geometry and magnetic property of [Fe(CN)6]4- area)d2sp3, octahedral, diamagnetib)d2sp3, octahedral, paramagneticc)sp3d2, octahedral, diamagneticd)sp3d2, octahedral, paramagneticCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When crystals of CuSO4 . 4NH3 are dissolved in water, there is hardly any evidence for the presence of Cu2+ ions or ammonia molecules. A new ion [Cu(NH3)4]2+ is furnished in which ammonia molecules are directly linked with the metal ion. Similarly, aqueous solution of Fe(CN)2 .4KCNdoes not give tests of Fe2+ and CN-ions but give test for new ion [Fe(CN)6]4-called ferrocyanide ion.Q.The hybridisation, geometry and magnetic property of [Fe(CN)6]4- area)d2sp3, octahedral, diamagnetib)d2sp3, octahedral, paramagneticc)sp3d2, octahedral, diamagneticd)sp3d2, octahedral, paramagneticCorrect answer is option 'A'. Can you explain this answer?.
Solutions for When crystals of CuSO4 . 4NH3 are dissolved in water, there is hardly any evidence for the presence of Cu2+ ions or ammonia molecules. A new ion [Cu(NH3)4]2+ is furnished in which ammonia molecules are directly linked with the metal ion. Similarly, aqueous solution of Fe(CN)2 .4KCNdoes not give tests of Fe2+ and CN-ions but give test for new ion [Fe(CN)6]4-called ferrocyanide ion.Q.The hybridisation, geometry and magnetic property of [Fe(CN)6]4- area)d2sp3, octahedral, diamagnetib)d2sp3, octahedral, paramagneticc)sp3d2, octahedral, diamagneticd)sp3d2, octahedral, paramagneticCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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Here you can find the meaning of When crystals of CuSO4 . 4NH3 are dissolved in water, there is hardly any evidence for the presence of Cu2+ ions or ammonia molecules. A new ion [Cu(NH3)4]2+ is furnished in which ammonia molecules are directly linked with the metal ion. Similarly, aqueous solution of Fe(CN)2 .4KCNdoes not give tests of Fe2+ and CN-ions but give test for new ion [Fe(CN)6]4-called ferrocyanide ion.Q.The hybridisation, geometry and magnetic property of [Fe(CN)6]4- area)d2sp3, octahedral, diamagnetib)d2sp3, octahedral, paramagneticc)sp3d2, octahedral, diamagneticd)sp3d2, octahedral, paramagneticCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
When crystals of CuSO4 . 4NH3 are dissolved in water, there is hardly any evidence for the presence of Cu2+ ions or ammonia molecules. A new ion [Cu(NH3)4]2+ is furnished in which ammonia molecules are directly linked with the metal ion. Similarly, aqueous solution of Fe(CN)2 .4KCNdoes not give tests of Fe2+ and CN-ions but give test for new ion [Fe(CN)6]4-called ferrocyanide ion.Q.The hybridisation, geometry and magnetic property of [Fe(CN)6]4- area)d2sp3, octahedral, diamagnetib)d2sp3, octahedral, paramagneticc)sp3d2, octahedral, diamagneticd)sp3d2, octahedral, paramagneticCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for When crystals of CuSO4 . 4NH3 are dissolved in water, there is hardly any evidence for the presence of Cu2+ ions or ammonia molecules. A new ion [Cu(NH3)4]2+ is furnished in which ammonia molecules are directly linked with the metal ion. Similarly, aqueous solution of Fe(CN)2 .4KCNdoes not give tests of Fe2+ and CN-ions but give test for new ion [Fe(CN)6]4-called ferrocyanide ion.Q.The hybridisation, geometry and magnetic property of [Fe(CN)6]4- area)d2sp3, octahedral, diamagnetib)d2sp3, octahedral, paramagneticc)sp3d2, octahedral, diamagneticd)sp3d2, octahedral, paramagneticCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of When crystals of CuSO4 . 4NH3 are dissolved in water, there is hardly any evidence for the presence of Cu2+ ions or ammonia molecules. A new ion [Cu(NH3)4]2+ is furnished in which ammonia molecules are directly linked with the metal ion. Similarly, aqueous solution of Fe(CN)2 .4KCNdoes not give tests of Fe2+ and CN-ions but give test for new ion [Fe(CN)6]4-called ferrocyanide ion.Q.The hybridisation, geometry and magnetic property of [Fe(CN)6]4- area)d2sp3, octahedral, diamagnetib)d2sp3, octahedral, paramagneticc)sp3d2, octahedral, diamagneticd)sp3d2, octahedral, paramagneticCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice When crystals of CuSO4 . 4NH3 are dissolved in water, there is hardly any evidence for the presence of Cu2+ ions or ammonia molecules. A new ion [Cu(NH3)4]2+ is furnished in which ammonia molecules are directly linked with the metal ion. Similarly, aqueous solution of Fe(CN)2 .4KCNdoes not give tests of Fe2+ and CN-ions but give test for new ion [Fe(CN)6]4-called ferrocyanide ion.Q.The hybridisation, geometry and magnetic property of [Fe(CN)6]4- area)d2sp3, octahedral, diamagnetib)d2sp3, octahedral, paramagneticc)sp3d2, octahedral, diamagneticd)sp3d2, octahedral, paramagneticCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice Class 12 tests.
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