If the equation x2 + bx + 45 = 0 (b ∈ R) has conjugate complex roots a...
Solution:
Given equation is x2 - bx + 45 = 0. Let the roots of the equation be z1 and z2. As the roots are conjugate complex, they can be written as z1 = a + ib and z2 = a - ib.
Using sum and product of roots, we can write:
z1 + z2 = 2a = b (i)
z1z2 = a2 + b2 = 45 (ii)
Also, |z1| = |z2| = 2√10.
Using modulus of complex numbers, we get:
|z1| = √(a2 + b2) = 2√10
Squaring both sides, we get:
a2 + b2 = 40 (iii)
Solving equations (ii) and (iii), we get:
a2 = 5 and b2 = 35
Substituting these values in equation (i), we get:
b = ±√(5×35) = ±√175
As the roots are conjugate complex, b must be negative. Therefore, b = -√175.
Now, we can check which option satisfies this value of b:
Option (2) b2 - b = 72
Substituting b = -√175, we get:
175 + √175 ≠ 72
Therefore, option (2) is not correct.
Option (1) b2 + b = 30
Substituting b = -√175, we get:
175 - √175 = 30
Option (3) b2 - b = 42
Substituting b = -√175, we get:
175 + √175 ≠ 42
Therefore, option (3) is not correct.
Option (4) b2 + b = 12
Substituting b = -√175, we get:
175 - √175 ≠ 12
Therefore, option (4) is not correct.
Hence, the correct option is (1) b2 + b = 30.
If the equation x2 + bx + 45 = 0 (b ∈ R) has conjugate complex roots a...