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A father is 30 times older than his son. 18 years later, he will be only thrice as old as his son. Father's present age in years is
- a)25
- b)30
- c)40
- d)45
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
A father is 30 times older than his son. 18 years later, he will be on...
F = 30 S
or, S = F/30
Also, F + 18 = 3(S + 18)
∴ F + 18 = 3( F/30 + 18)
or, F + 18 = F/10 + 54
or, F - F/10 = 36 or, 9/10 F = 36
or, F = 36 x 10/9 = 40 yrs
or, S = F/30
Also, F + 18 = 3(S + 18)
∴ F + 18 = 3( F/30 + 18)
or, F + 18 = F/10 + 54
or, F - F/10 = 36 or, 9/10 F = 36
or, F = 36 x 10/9 = 40 yrs
Most Upvoted Answer
A father is 30 times older than his son. 18 years later, he will be on...
To solve this problem, let's assume the present age of the son is S years and the present age of the father is F years.
Let's break down the information given in the question:
1. "A father is 30 times older than his son."
This can be written as F = 30S.
2. "18 years later, he will be only thrice as old as his son."
After 18 years, the age of the son will be S + 18 and the age of the father will be F + 18. According to the second statement, we can write the equation:
F + 18 = 3(S + 18).
Now, let's solve these equations to find the present age of the father:
1. Substitute the value of F from equation 1 into equation 2:
30S + 18 = 3(S + 18).
2. Distribute 3 to S and 18:
30S + 18 = 3S + 54.
3. Simplify the equation by combining like terms:
30S - 3S = 54 - 18,
27S = 36.
4. Divide both sides of the equation by 27:
S = 36 / 27,
S = 4/3.
5. Now, substitute the value of S into equation 1 to find the father's age:
F = 30S,
F = 30 * (4/3),
F = 40.
Therefore, the present age of the father is 40 years, which corresponds to option C.
Let's break down the information given in the question:
1. "A father is 30 times older than his son."
This can be written as F = 30S.
2. "18 years later, he will be only thrice as old as his son."
After 18 years, the age of the son will be S + 18 and the age of the father will be F + 18. According to the second statement, we can write the equation:
F + 18 = 3(S + 18).
Now, let's solve these equations to find the present age of the father:
1. Substitute the value of F from equation 1 into equation 2:
30S + 18 = 3(S + 18).
2. Distribute 3 to S and 18:
30S + 18 = 3S + 54.
3. Simplify the equation by combining like terms:
30S - 3S = 54 - 18,
27S = 36.
4. Divide both sides of the equation by 27:
S = 36 / 27,
S = 4/3.
5. Now, substitute the value of S into equation 1 to find the father's age:
F = 30S,
F = 30 * (4/3),
F = 40.
Therefore, the present age of the father is 40 years, which corresponds to option C.
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A father is 30 times older than his son. 18 years later, he will be only thrice as old as his son. Fathers present age in years isa)25b)30c)40d)45Correct answer is option 'C'. Can you explain this answer?
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