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The number of solutions of the two equations 4x-y=2 and 2x-8y+4=0 is 
  • a)
    Zero
  • b)
    One 
  • c)
    Two
  • d)
    Infinitely many 
Correct answer is option 'B'. Can you explain this answer?
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The number of solutions of the two equations 4x-y=2 and 2x-8y+4=0 isa)...
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Most Upvoted Answer
The number of solutions of the two equations 4x-y=2 and 2x-8y+4=0 isa)...
Explanation:

To find the number of solutions of the given equations, we can start by analyzing the system of equations and determining the relationship between the two equations.

The given system of equations is:
1) 4x - y = 2
2) 2x - 8y + 4 = 0

Step 1: Simplify the equations
To make the equations easier to work with, we can rearrange them to isolate the variables on one side:

Equation 1: 4x - y = 2
Rearranging, we have:
y = 4x - 2

Equation 2: 2x - 8y + 4 = 0
Rearranging, we have:
2x - 8y = -4
Dividing by 2, we get:
x - 4y = -2

Step 2: Compare the equations
By comparing the two equations, we can see that they have the same slope (4) and different y-intercepts (-2 and -2). This indicates that the equations represent two parallel lines in the coordinate plane.

Step 3: Determine the number of solutions
Since the two equations represent parallel lines, they will never intersect. Therefore, there are no common points of intersection and no solutions to the system of equations.

Conclusion:
The number of solutions of the given system of equations is zero (option A).
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The number of solutions of the two equations 4x-y=2 and 2x-8y+4=0 isa)Zerob)Onec)Twod)Infinitely manyCorrect answer is option 'B'. Can you explain this answer?
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