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Gold is 14 times as heavy as water and copper is 6 times as heavy as water. In what ratio should to these be mixed to get an alloy 11 times as heavy as water. 
  • a)
    3 : 5 
  • b)
    5 : 3 
  • c)
    4 : 5 
  • d)
    5 : 4 
Correct answer is option 'B'. Can you explain this answer?
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Concept:
To find the ratio in which gold and copper should be mixed to get an alloy 11 times as heavy as water, we can set up a proportion based on their relative densities compared to water.

Given data:
- Gold is 14 times as heavy as water
- Copper is 6 times as heavy as water
- Alloy is 11 times as heavy as water

Calculations:
Let the ratio of gold to copper be x:y.
The density of the alloy can be expressed as:
(14x + 6y) / (x + y) = 11
Solving this equation, we get:
14x + 6y = 11x + 11y
3x = 5y
x/y = 5/3

Conclusion:
Therefore, gold and copper should be mixed in the ratio of 5:3 to get an alloy 11 times as heavy as water. The correct answer is option B (5:3).
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Question Description
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