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A hydrogen like species having atomic number Z = 2, in ground state, is excited by means of electromagnetic radiation of frequency 1.315 × 1016 Hz. How many spectral lines will be observed in the emission spectrum? 
(Planck’s constant h = 4.14 × 10-15 eVs) 
  • a)
    Infinite  
  • b)
    Six  
  • c)
    zero  
  • d)
    Four  
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A hydrogen like species having atomic number Z = 2, in ground state, i...
E = hν = 4.14 × 10-15 × 1.315 × 1016 = 54.4 eV  
Energy of the given species in ground state is 

Ionization energy of the given species is = |E1| = 54.4 eV  
Thus the electron will get ionized and therefore become free.
So no spectral lines will be observed. 
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Most Upvoted Answer
A hydrogen like species having atomic number Z = 2, in ground state, i...

Explanation:

Ground State Excitation:
When a hydrogen-like species with atomic number Z = 2 is in its ground state, it means that the electron is in the lowest energy level possible.

Excitation by Electromagnetic Radiation:
When electromagnetic radiation of frequency 1.315 x 10^16 Hz is incident on the hydrogen-like species, it will cause the electron to move to a higher energy level.

Emission Spectrum:
However, since the hydrogen-like species only has two energy levels (ground state and excited state), when the electron falls back to the ground state, it will emit a single spectral line corresponding to the energy difference between the two levels.

Number of Spectral Lines:
In this case, only one spectral line will be observed in the emission spectrum because there are only two energy levels involved in the excitation and de-excitation process.

Therefore, the correct answer is option C) zero.
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A hydrogen like species having atomic number Z = 2, in ground state, is excited by means of electromagnetic radiation of frequency 1.315 1016 Hz. How many spectral lines will be observed in the emission spectrum?(Plancks constant h = 4.14 10-15 eVs)a)Infinite b)Six c)zero d)Four Correct answer is option 'C'. Can you explain this answer?
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A hydrogen like species having atomic number Z = 2, in ground state, is excited by means of electromagnetic radiation of frequency 1.315 1016 Hz. How many spectral lines will be observed in the emission spectrum?(Plancks constant h = 4.14 10-15 eVs)a)Infinite b)Six c)zero d)Four Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A hydrogen like species having atomic number Z = 2, in ground state, is excited by means of electromagnetic radiation of frequency 1.315 1016 Hz. How many spectral lines will be observed in the emission spectrum?(Plancks constant h = 4.14 10-15 eVs)a)Infinite b)Six c)zero d)Four Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A hydrogen like species having atomic number Z = 2, in ground state, is excited by means of electromagnetic radiation of frequency 1.315 1016 Hz. How many spectral lines will be observed in the emission spectrum?(Plancks constant h = 4.14 10-15 eVs)a)Infinite b)Six c)zero d)Four Correct answer is option 'C'. Can you explain this answer?.
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