the sum of the digit of a two digit number is 12 the number is fix tim...
So, it is given that, x+y=12
also given, 10x+y=6y
so, 10x=6y-y=5y
again 5y=10x
so, y=10x/5=2x
we already know that it is given
x+y=12, here we will put the value of
y as 2x
so, x+2x=12
3x=12 So, y=2x=2*4=8
x=12/3=4
Therefore the digit is (10*4)+8=48
the sum of the digit of a two digit number is 12 the number is fix tim...
Understanding the Problem
To solve the problem of finding a two-digit number where the sum of its digits is 12, we can break it down as follows:
- Let the two-digit number be represented as 10a + b, where:
- a is the tens digit
- b is the units digit
Sum of Digits
According to the problem:
- The sum of the digits, a + b = 12.
Finding Possible Values
- The possible values for a (tens digit) range from 1 to 9 (since it is a two-digit number).
- Therefore, we can list the pairs of (a, b) that satisfy the equation a + b = 12:
- If a = 3, then b = 9 → Number: 39
- If a = 4, then b = 8 → Number: 48
- If a = 5, then b = 7 → Number: 57
- If a = 6, then b = 6 → Number: 66
- If a = 7, then b = 5 → Number: 75
- If a = 8, then b = 4 → Number: 84
- If a = 9, then b = 3 → Number: 93
Selecting the Required Number
- The problem states that the number is fixed times the unit digit. If we let the two-digit number be N = 10a + b, we can formulate:
- N = k*b, where k is a fixed multiplier.
Conclusion
- The valid two-digit numbers whose digits sum to 12 are: 39, 48, 57, 66, 75, 84, 93.
- Depending on the value of k, you can substitute to find specific cases.
This structured approach helps in systematically identifying the solution!
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