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A two span continuous beam ABC is simply supported at A and C and is continuous over support B. Span AB = 6 m, BC = 6m. The beam carries a UDL of 2 t/m over both the spans. B is constant for the entire beam. The fixed end moment at B in span BA or BC would be
- a)12 t.m
- b)9 t.m
- c)8 t.m
- d)6 t.m
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
A two span continuous beam ABC is simply supported at A and C and is c...
Using three moment theorem,
as MA = Mc = 0
or MB = 9 t . m .
Hence Option (B) is Correct
For test on indeterminate analysis click on the following link :
Most Upvoted Answer
A two span continuous beam ABC is simply supported at A and C and is c...
Given data:
- Span AB = 6 m
- Span BC = 6 m
- Beam carries UDL of 2 t/m over both spans
- Beam is simply supported at A and C, and continuous over support B
- Fixed end moment at B in span BA or BC is to be determined
To find the fixed end moment at B in span BA or BC, we need to first calculate the reactions at supports A and C.
Calculation of Reactions:
- Since the beam is symmetrical, the reactions at supports A and C will be equal
- Let the reaction at support A and C be R
- The total load on the beam = UDL x length of span
- Total load on span AB = 2 t/m x 6 m = 12 t
- Total load on span BC = 2 t/m x 6 m = 12 t
- Total load on the beam = 12 t + 12 t = 24 t
- Summation of moments about support A = 0
- R x 6 m = 12 t x 3 m + 12 t x (3 m + 6 m/2)
- R = 18 t
Therefore, the reactions at supports A and C are 18 t each.
Calculation of Fixed End Moment at B:
- Since the beam is continuous over support B, the bending moment at B will be equal to the sum of the moments due to the loads on both spans
- Let the fixed end moment at B in span BA be M1 and in span BC be M2
- Bending moment due to UDL on span AB = UDL x (span/2)^2 = 2 t/m x (6 m / 2)^2 = 18 t.m
- Bending moment due to UDL on span BC = UDL x (span/2)^2 = 2 t/m x (6 m / 2)^2 = 18 t.m
- Bending moment at support B = M1 + M2
- From the continuity equation at support B, we have:
- M1 + M2 = R x (6 m/2) = 18 t x 3 m = 54 t.m
- Substituting the values of M1 and M2, we get:
- 2M1 = 54 t.m - 18 t.m = 36 t.m
- M1 = 18 t.m
- Therefore, the fixed end moment at B in span BA or BC is 9 t.m (half of M1)
Hence, option 'B' is the correct answer.
- Span AB = 6 m
- Span BC = 6 m
- Beam carries UDL of 2 t/m over both spans
- Beam is simply supported at A and C, and continuous over support B
- Fixed end moment at B in span BA or BC is to be determined
To find the fixed end moment at B in span BA or BC, we need to first calculate the reactions at supports A and C.
Calculation of Reactions:
- Since the beam is symmetrical, the reactions at supports A and C will be equal
- Let the reaction at support A and C be R
- The total load on the beam = UDL x length of span
- Total load on span AB = 2 t/m x 6 m = 12 t
- Total load on span BC = 2 t/m x 6 m = 12 t
- Total load on the beam = 12 t + 12 t = 24 t
- Summation of moments about support A = 0
- R x 6 m = 12 t x 3 m + 12 t x (3 m + 6 m/2)
- R = 18 t
Therefore, the reactions at supports A and C are 18 t each.
Calculation of Fixed End Moment at B:
- Since the beam is continuous over support B, the bending moment at B will be equal to the sum of the moments due to the loads on both spans
- Let the fixed end moment at B in span BA be M1 and in span BC be M2
- Bending moment due to UDL on span AB = UDL x (span/2)^2 = 2 t/m x (6 m / 2)^2 = 18 t.m
- Bending moment due to UDL on span BC = UDL x (span/2)^2 = 2 t/m x (6 m / 2)^2 = 18 t.m
- Bending moment at support B = M1 + M2
- From the continuity equation at support B, we have:
- M1 + M2 = R x (6 m/2) = 18 t x 3 m = 54 t.m
- Substituting the values of M1 and M2, we get:
- 2M1 = 54 t.m - 18 t.m = 36 t.m
- M1 = 18 t.m
- Therefore, the fixed end moment at B in span BA or BC is 9 t.m (half of M1)
Hence, option 'B' is the correct answer.
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A two span continuous beam ABC is simply supported at A and C and is continuous over support B. Span AB = 6 m, BC = 6m. The beam carries a UDL of 2 t/m over both the spans. B is constant for the entire beam. The fixed end moment at B in span BA or BC would bea)12 t.mb)9 t.mc)8 t.md)6 t.mCorrect answer is option 'B'. Can you explain this answer?
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A two span continuous beam ABC is simply supported at A and C and is continuous over support B. Span AB = 6 m, BC = 6m. The beam carries a UDL of 2 t/m over both the spans. B is constant for the entire beam. The fixed end moment at B in span BA or BC would bea)12 t.mb)9 t.mc)8 t.md)6 t.mCorrect answer is option 'B'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A two span continuous beam ABC is simply supported at A and C and is continuous over support B. Span AB = 6 m, BC = 6m. The beam carries a UDL of 2 t/m over both the spans. B is constant for the entire beam. The fixed end moment at B in span BA or BC would bea)12 t.mb)9 t.mc)8 t.md)6 t.mCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A two span continuous beam ABC is simply supported at A and C and is continuous over support B. Span AB = 6 m, BC = 6m. The beam carries a UDL of 2 t/m over both the spans. B is constant for the entire beam. The fixed end moment at B in span BA or BC would bea)12 t.mb)9 t.mc)8 t.md)6 t.mCorrect answer is option 'B'. Can you explain this answer?.
A two span continuous beam ABC is simply supported at A and C and is continuous over support B. Span AB = 6 m, BC = 6m. The beam carries a UDL of 2 t/m over both the spans. B is constant for the entire beam. The fixed end moment at B in span BA or BC would bea)12 t.mb)9 t.mc)8 t.md)6 t.mCorrect answer is option 'B'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A two span continuous beam ABC is simply supported at A and C and is continuous over support B. Span AB = 6 m, BC = 6m. The beam carries a UDL of 2 t/m over both the spans. B is constant for the entire beam. The fixed end moment at B in span BA or BC would bea)12 t.mb)9 t.mc)8 t.md)6 t.mCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A two span continuous beam ABC is simply supported at A and C and is continuous over support B. Span AB = 6 m, BC = 6m. The beam carries a UDL of 2 t/m over both the spans. B is constant for the entire beam. The fixed end moment at B in span BA or BC would bea)12 t.mb)9 t.mc)8 t.md)6 t.mCorrect answer is option 'B'. Can you explain this answer?.
Solutions for A two span continuous beam ABC is simply supported at A and C and is continuous over support B. Span AB = 6 m, BC = 6m. The beam carries a UDL of 2 t/m over both the spans. B is constant for the entire beam. The fixed end moment at B in span BA or BC would bea)12 t.mb)9 t.mc)8 t.md)6 t.mCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Civil Engineering (CE).
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A two span continuous beam ABC is simply supported at A and C and is continuous over support B. Span AB = 6 m, BC = 6m. The beam carries a UDL of 2 t/m over both the spans. B is constant for the entire beam. The fixed end moment at B in span BA or BC would bea)12 t.mb)9 t.mc)8 t.md)6 t.mCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for A two span continuous beam ABC is simply supported at A and C and is continuous over support B. Span AB = 6 m, BC = 6m. The beam carries a UDL of 2 t/m over both the spans. B is constant for the entire beam. The fixed end moment at B in span BA or BC would bea)12 t.mb)9 t.mc)8 t.md)6 t.mCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of A two span continuous beam ABC is simply supported at A and C and is continuous over support B. Span AB = 6 m, BC = 6m. The beam carries a UDL of 2 t/m over both the spans. B is constant for the entire beam. The fixed end moment at B in span BA or BC would bea)12 t.mb)9 t.mc)8 t.md)6 t.mCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
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