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How many hydrogen bonds are present b/w complementary nitrogen bases of a DNA with 5 turns and 20 Adenines ?
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How many hydrogen bonds are present b/w complementary nitrogen bases o...
10 base pairs per helix/ turn. here 5 turns so, 50 base pairs. as 20% A in one strand then 20% T is present in its complementary strand forming A+T => 2 H-bond( total 40%). remaing 60% formed by G+C =>3 H-bond (30% each on complementary strand). since, for A+T 40% of 50bp is 40×50/100= 20 A+T bp, 2×20= 40 H-bond. & for G+C 60×50/100= 30 G+C bp. 3×30= 90 H-bonds. total 90+40=130 H-bond present in DNA.
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How many hydrogen bonds are present b/w complementary nitrogen bases o...
Answer:

Introduction:
DNA stands for deoxyribonucleic acid, which is a double-stranded, helical structure. It is made up of four nitrogenous bases: Adenine (A), Guanine (G), Cytosine (C), and Thymine (T). These bases pair up with each other through hydrogen bonds, with A pairing with T and G pairing with C. The number of hydrogen bonds between these pairs determines the stability of the DNA molecule.

Calculation:
- A DNA molecule with 5 turns will have 10 base pairs per turn.
- Therefore, this DNA molecule will have 50 base pairs (10 base pairs/turn x 5 turns).
- As there are 20 Adenines in the DNA molecule, there will be 20 Thymine bases to pair with them, making a total of 40 A-T base pairs.
- Each A-T base pair is held together by two hydrogen bonds.
- Therefore, the total number of hydrogen bonds between the complementary nitrogen bases in this DNA molecule will be 2 x 40 = 80.

Conclusion:
In conclusion, a DNA molecule with 5 turns and 20 Adenines will have a total of 80 hydrogen bonds between the complementary nitrogen bases. These hydrogen bonds play a crucial role in maintaining the stability and integrity of the DNA molecule.
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How many hydrogen bonds are present b/w complementary nitrogen bases of a DNA with 5 turns and 20 Adenines ?
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