Defence Exam > Defence Questions > The H.C.F and the product of two numbers are ...
Start Learning for Free
The H.C.F and the product of two numbers are 15 and 6300 respectively. The number of possible pairs of numbers is:
- a)2
- b)3
- c)4
- d)7
Correct answer is option 'A'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
The H.C.F and the product of two numbers are 15 and 6300 respectively....
Most Upvoted Answer
The H.C.F and the product of two numbers are 15 and 6300 respectively....
The H.C.F and the product of two numbers
Given:
- H.C.F (Highest Common Factor) of two numbers = 15
- Product of the two numbers = 6300
To find the number of possible pairs of numbers, we need to find the factors of 6300 and check which pairs have a H.C.F of 15.
Factors of 6300
To find the factors of 6300, we can prime factorize it.
Prime factorization of 6300:
6300 = 2 * 3 * 3 * 5 * 5 * 7
Finding the factors
To find the factors, we can start with the smallest prime factor (2) and systematically increase it to the next prime factor (3, 5, 7) while keeping track of the number of times each prime factor is used.
Factors of 6300:
2^0 * 3^0 * 5^0 * 7^0 = 1 (no prime factors used)
2^1 * 3^0 * 5^0 * 7^0 = 2
2^0 * 3^1 * 5^0 * 7^0 = 3
2^2 * 3^0 * 5^0 * 7^0 = 4
2^1 * 3^1 * 5^0 * 7^0 = 6
2^0 * 3^0 * 5^1 * 7^0 = 5
2^3 * 3^0 * 5^0 * 7^0 = 8
2^2 * 3^1 * 5^0 * 7^0 = 12
2^1 * 3^2 * 5^0 * 7^0 = 18
2^0 * 3^0 * 5^0 * 7^1 = 7
2^4 * 3^0 * 5^0 * 7^0 = 16
2^3 * 3^1 * 5^0 * 7^0 = 24
2^2 * 3^0 * 5^1 * 7^0 = 20
2^1 * 3^1 * 5^1 * 7^0 = 30
2^0 * 3^2 * 5^0 * 7^0 = 9
2^5 * 3^0 * 5^0 * 7^0 = 32
2^4 * 3^1 * 5^0 * 7^0 = 48
2^3 * 3^2 * 5^0 * 7^0 = 72
2^2 * 3^0 * 5^1 * 7^0 = 40
2^1 * 3^1 * 5^1 * 7^0 = 60
2^0 * 3^3 * 5^0 * 7^0 = 27
2^6 * 3^0 * 5^0 * 7^0 = 64
2^5 * 3^1 * 5^0 * 7^0
Given:
- H.C.F (Highest Common Factor) of two numbers = 15
- Product of the two numbers = 6300
To find the number of possible pairs of numbers, we need to find the factors of 6300 and check which pairs have a H.C.F of 15.
Factors of 6300
To find the factors of 6300, we can prime factorize it.
Prime factorization of 6300:
6300 = 2 * 3 * 3 * 5 * 5 * 7
Finding the factors
To find the factors, we can start with the smallest prime factor (2) and systematically increase it to the next prime factor (3, 5, 7) while keeping track of the number of times each prime factor is used.
Factors of 6300:
2^0 * 3^0 * 5^0 * 7^0 = 1 (no prime factors used)
2^1 * 3^0 * 5^0 * 7^0 = 2
2^0 * 3^1 * 5^0 * 7^0 = 3
2^2 * 3^0 * 5^0 * 7^0 = 4
2^1 * 3^1 * 5^0 * 7^0 = 6
2^0 * 3^0 * 5^1 * 7^0 = 5
2^3 * 3^0 * 5^0 * 7^0 = 8
2^2 * 3^1 * 5^0 * 7^0 = 12
2^1 * 3^2 * 5^0 * 7^0 = 18
2^0 * 3^0 * 5^0 * 7^1 = 7
2^4 * 3^0 * 5^0 * 7^0 = 16
2^3 * 3^1 * 5^0 * 7^0 = 24
2^2 * 3^0 * 5^1 * 7^0 = 20
2^1 * 3^1 * 5^1 * 7^0 = 30
2^0 * 3^2 * 5^0 * 7^0 = 9
2^5 * 3^0 * 5^0 * 7^0 = 32
2^4 * 3^1 * 5^0 * 7^0 = 48
2^3 * 3^2 * 5^0 * 7^0 = 72
2^2 * 3^0 * 5^1 * 7^0 = 40
2^1 * 3^1 * 5^1 * 7^0 = 60
2^0 * 3^3 * 5^0 * 7^0 = 27
2^6 * 3^0 * 5^0 * 7^0 = 64
2^5 * 3^1 * 5^0 * 7^0
|
Explore Courses for Defence exam
|
|
Similar Defence Doubts
The H.C.F and the product of two numbers are 15 and 6300 respectively. The number of possible pairs of numbers is:a)2b)3c)4d)7Correct answer is option 'A'. Can you explain this answer?
Question Description
The H.C.F and the product of two numbers are 15 and 6300 respectively. The number of possible pairs of numbers is:a)2b)3c)4d)7Correct answer is option 'A'. Can you explain this answer? for Defence 2024 is part of Defence preparation. The Question and answers have been prepared according to the Defence exam syllabus. Information about The H.C.F and the product of two numbers are 15 and 6300 respectively. The number of possible pairs of numbers is:a)2b)3c)4d)7Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Defence 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The H.C.F and the product of two numbers are 15 and 6300 respectively. The number of possible pairs of numbers is:a)2b)3c)4d)7Correct answer is option 'A'. Can you explain this answer?.
The H.C.F and the product of two numbers are 15 and 6300 respectively. The number of possible pairs of numbers is:a)2b)3c)4d)7Correct answer is option 'A'. Can you explain this answer? for Defence 2024 is part of Defence preparation. The Question and answers have been prepared according to the Defence exam syllabus. Information about The H.C.F and the product of two numbers are 15 and 6300 respectively. The number of possible pairs of numbers is:a)2b)3c)4d)7Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Defence 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The H.C.F and the product of two numbers are 15 and 6300 respectively. The number of possible pairs of numbers is:a)2b)3c)4d)7Correct answer is option 'A'. Can you explain this answer?.
Solutions for The H.C.F and the product of two numbers are 15 and 6300 respectively. The number of possible pairs of numbers is:a)2b)3c)4d)7Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Defence.
Download more important topics, notes, lectures and mock test series for Defence Exam by signing up for free.
Here you can find the meaning of The H.C.F and the product of two numbers are 15 and 6300 respectively. The number of possible pairs of numbers is:a)2b)3c)4d)7Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The H.C.F and the product of two numbers are 15 and 6300 respectively. The number of possible pairs of numbers is:a)2b)3c)4d)7Correct answer is option 'A'. Can you explain this answer?, a detailed solution for The H.C.F and the product of two numbers are 15 and 6300 respectively. The number of possible pairs of numbers is:a)2b)3c)4d)7Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of The H.C.F and the product of two numbers are 15 and 6300 respectively. The number of possible pairs of numbers is:a)2b)3c)4d)7Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The H.C.F and the product of two numbers are 15 and 6300 respectively. The number of possible pairs of numbers is:a)2b)3c)4d)7Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice Defence tests.
|
|
Explore Courses for Defence exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup