Class 12 Exam  >  Class 12 Questions  >  Molality of 1M solution of NaNO3 solution (de... Start Learning for Free
Molality of 1M solution of NaNO3 solution (density of solution is 1.25 g mL^-1 and mol.wt. of NaNO3=85 g mol^-1)is?
Most Upvoted Answer
Molality of 1M solution of NaNO3 solution (density of solution is 1.25...
Calculation of Molality of the Solution

To calculate the molality of a solution, we need to know the moles of solute and the mass of the solvent. In this case, the solute is NaNO3 and the solvent is water.

Step 1: Calculate the moles of NaNO3
Given that the concentration of NaNO3 solution is 1M, we can determine the moles of NaNO3 using the formula:

Molarity (M) = Moles of solute / Volume of solution (L)

Rearranging the formula to solve for moles of solute:

Moles of solute = Molarity (M) * Volume of solution (L)

Since the volume of the solution is not given, we cannot directly calculate the moles of NaNO3. However, we can use the density of the solution to find the volume.

Step 2: Calculate the volume of the solution
The density of the solution is given as 1.25 g/mL. Since the density is the mass per unit volume, we can rearrange the formula to solve for volume:

Volume of solution (mL) = Mass of solution (g) / Density of solution (g/mL)

Assuming we have 1 L of the solution (1000 mL), we can calculate the mass of the solution as follows:

Mass of solution (g) = Volume of solution (mL) * Density of solution (g/mL)

Step 3: Calculate the moles of NaNO3
Now that we have the mass of the solution, we can substitute it into the formula to calculate the moles of NaNO3:

Moles of NaNO3 = Molarity (M) * Volume of solution (L)

Step 4: Calculate the molality of the solution
Finally, we can calculate the molality of the solution using the formula:

Molality (m) = Moles of solute / Mass of solvent (kg)

Since water is the solvent, we need to convert the mass of water from grams to kilograms:

Mass of solvent (kg) = Mass of solvent (g) / 1000

Step 5: Substitute the values and calculate the molality
Now we can substitute the values into the formula and calculate the molality:

Molality (m) = Moles of NaNO3 / Mass of water (kg)

Final Answer:

By following these steps and substituting the appropriate values, you can calculate the molality of the 1M NaNO3 solution.
Community Answer
Molality of 1M solution of NaNO3 solution (density of solution is 1.25...
0.858 m
Explore Courses for Class 12 exam
Molality of 1M solution of NaNO3 solution (density of solution is 1.25 g mL^-1 and mol.wt. of NaNO3=85 g mol^-1)is?
Question Description
Molality of 1M solution of NaNO3 solution (density of solution is 1.25 g mL^-1 and mol.wt. of NaNO3=85 g mol^-1)is? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Molality of 1M solution of NaNO3 solution (density of solution is 1.25 g mL^-1 and mol.wt. of NaNO3=85 g mol^-1)is? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Molality of 1M solution of NaNO3 solution (density of solution is 1.25 g mL^-1 and mol.wt. of NaNO3=85 g mol^-1)is?.
Solutions for Molality of 1M solution of NaNO3 solution (density of solution is 1.25 g mL^-1 and mol.wt. of NaNO3=85 g mol^-1)is? in English & in Hindi are available as part of our courses for Class 12. Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
Here you can find the meaning of Molality of 1M solution of NaNO3 solution (density of solution is 1.25 g mL^-1 and mol.wt. of NaNO3=85 g mol^-1)is? defined & explained in the simplest way possible. Besides giving the explanation of Molality of 1M solution of NaNO3 solution (density of solution is 1.25 g mL^-1 and mol.wt. of NaNO3=85 g mol^-1)is?, a detailed solution for Molality of 1M solution of NaNO3 solution (density of solution is 1.25 g mL^-1 and mol.wt. of NaNO3=85 g mol^-1)is? has been provided alongside types of Molality of 1M solution of NaNO3 solution (density of solution is 1.25 g mL^-1 and mol.wt. of NaNO3=85 g mol^-1)is? theory, EduRev gives you an ample number of questions to practice Molality of 1M solution of NaNO3 solution (density of solution is 1.25 g mL^-1 and mol.wt. of NaNO3=85 g mol^-1)is? tests, examples and also practice Class 12 tests.
Explore Courses for Class 12 exam
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev