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Density of a 2.05 M solution of acetic acid in water is 1.02 g/mL. The molality of the solution is -
[AIEEE 2006]
- a)3.28 mol kg-1
- b)2.28 mol kg-1
- c)0.44 mol kg-1
- d)1.14 mol kg-1
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Density of a 2.05 M solution of acetic acid in water is 1.02 g/mL. The...
The correct answer is option B
weight of acetic acid =2.05×60=123g2.05×60=123g
Weight of solution =1000×1.02=1020g=1000×1.02=1020g
∴ Weight of water=(1020−123)=897g
=2.285 mol kg-1
weight of acetic acid =2.05×60=123g2.05×60=123g
Weight of solution =1000×1.02=1020g=1000×1.02=1020g
∴ Weight of water=(1020−123)=897g
=2.285 mol kg-1
Most Upvoted Answer
Density of a 2.05 M solution of acetic acid in water is 1.02 g/mL. The...
Given:
Density of solution = 1.02 g/mL
Concentration of acetic acid = 2.05 M
Molality is defined as the number of moles of solute per kilogram of solvent.
To find the molality, we need to first calculate the mass of the solvent present in one liter of the solution.
Calculations:
1 liter of the solution contains:
Mass of solution = Volume x Density
= 1 L x 1.02 g/mL
= 1020 g
Mass of acetic acid in 1 liter of solution = Concentration x Volume
= 2.05 mol/L x 1 L
= 2.05 moles
Mass of water in 1 liter of solution = Total mass - Mass of acetic acid
= 1020 g - 2.05 mol x 60.05 g/mol
= 888.975 g
Molality = moles of solute / kg of solvent
= 2.05 moles / 0.888975 kg
= 2.306 mol/kg
Round off the answer to two significant figures:
Molality = 2.3 mol/kg
Therefore, the correct option is (B) 2.28 mol/kg.
Density of solution = 1.02 g/mL
Concentration of acetic acid = 2.05 M
Molality is defined as the number of moles of solute per kilogram of solvent.
To find the molality, we need to first calculate the mass of the solvent present in one liter of the solution.
Calculations:
1 liter of the solution contains:
Mass of solution = Volume x Density
= 1 L x 1.02 g/mL
= 1020 g
Mass of acetic acid in 1 liter of solution = Concentration x Volume
= 2.05 mol/L x 1 L
= 2.05 moles
Mass of water in 1 liter of solution = Total mass - Mass of acetic acid
= 1020 g - 2.05 mol x 60.05 g/mol
= 888.975 g
Molality = moles of solute / kg of solvent
= 2.05 moles / 0.888975 kg
= 2.306 mol/kg
Round off the answer to two significant figures:
Molality = 2.3 mol/kg
Therefore, the correct option is (B) 2.28 mol/kg.
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Density of a 2.05 M solution of acetic acid in water is 1.02 g/mL. The...
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Density of a 2.05 M solution of acetic acid in water is 1.02 g/mL. The molality of the solution is -[AIEEE 2006]a)3.28 mol kg-1b)2.28 mol kg-1c)0.44 mol kg-1d)1.14 mol kg-1Correct answer is option 'B'. Can you explain this answer?
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Density of a 2.05 M solution of acetic acid in water is 1.02 g/mL. The molality of the solution is -[AIEEE 2006]a)3.28 mol kg-1b)2.28 mol kg-1c)0.44 mol kg-1d)1.14 mol kg-1Correct answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Density of a 2.05 M solution of acetic acid in water is 1.02 g/mL. The molality of the solution is -[AIEEE 2006]a)3.28 mol kg-1b)2.28 mol kg-1c)0.44 mol kg-1d)1.14 mol kg-1Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Density of a 2.05 M solution of acetic acid in water is 1.02 g/mL. The molality of the solution is -[AIEEE 2006]a)3.28 mol kg-1b)2.28 mol kg-1c)0.44 mol kg-1d)1.14 mol kg-1Correct answer is option 'B'. Can you explain this answer?.
Density of a 2.05 M solution of acetic acid in water is 1.02 g/mL. The molality of the solution is -[AIEEE 2006]a)3.28 mol kg-1b)2.28 mol kg-1c)0.44 mol kg-1d)1.14 mol kg-1Correct answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Density of a 2.05 M solution of acetic acid in water is 1.02 g/mL. The molality of the solution is -[AIEEE 2006]a)3.28 mol kg-1b)2.28 mol kg-1c)0.44 mol kg-1d)1.14 mol kg-1Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Density of a 2.05 M solution of acetic acid in water is 1.02 g/mL. The molality of the solution is -[AIEEE 2006]a)3.28 mol kg-1b)2.28 mol kg-1c)0.44 mol kg-1d)1.14 mol kg-1Correct answer is option 'B'. Can you explain this answer?.
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Density of a 2.05 M solution of acetic acid in water is 1.02 g/mL. The molality of the solution is -[AIEEE 2006]a)3.28 mol kg-1b)2.28 mol kg-1c)0.44 mol kg-1d)1.14 mol kg-1Correct answer is option 'B'. Can you explain this answer?, a detailed solution for Density of a 2.05 M solution of acetic acid in water is 1.02 g/mL. The molality of the solution is -[AIEEE 2006]a)3.28 mol kg-1b)2.28 mol kg-1c)0.44 mol kg-1d)1.14 mol kg-1Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of Density of a 2.05 M solution of acetic acid in water is 1.02 g/mL. The molality of the solution is -[AIEEE 2006]a)3.28 mol kg-1b)2.28 mol kg-1c)0.44 mol kg-1d)1.14 mol kg-1Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
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