How many minimum meiotic division required to form 1000male gametes?
1 meiotic division------4 male gamates.........
? no. of meiotic division ---1000 male gametes...Here; its 1000/4=250 divisions...
-》u can remember the formula "n=x/4" for this ...
Here 'x' stands for "male gametes" & 'n' stands for "no. of divisions" ..;its for calculating no. of meiotic divisions involved in the formation of male gamete....
-》u can remember the formula "n=x" for no. of mitotic divisions involved in the formation of female gamete..in this case "n=no. of divisions" & "x=female gamete"...
-》u can remember the formula "n= x + x/4" for calculating the no. of seed formation...
Here in this formula..'x' denotes the contribution of "female part" ...where as 'x/4' denotes the contribution of "male part" in the seed formation....
How many minimum meiotic division required to form 1000male gametes?
1 meiotic division forms 4 gamets
then,
1 gamet will form in 1/4 meiotic division
therefore,
1000 gamet will form in 1/4 ×1000 = 250
hence 250 meiotic division required to form 1000 gamets
simple unitary method no need to learn any formula