JEE Exam > JEE Questions > After electrolysis of a NaCl solution with in...
Start Learning for Free
After electrolysis of a NaCl solution with inert electrodes for a certain period of time, 60 ml of the solution was left which was found to be 1 N in NaOH. During the same time 31.75 g of Cu was deposited in a Cu voltameter in series with the electrolytic cell. Calculate the percentage of the theoretical yield of the sodium hydroxide obtained.
- a)3
- b)6
- c)5
- d)4
Correct answer is '6'. Can you explain this answer?
Verified Answer
After electrolysis of a NaCl solution with inert electrodes for a cert...
No. of eq. of NaOH that can be produced theoretically for 100% current efficiency = no of equivalents of NaCl decomposed = no of eq. of Cu deposited
No. of eq. of NaOH produced experimentally = 
Most Upvoted Answer
After electrolysis of a NaCl solution with inert electrodes for a cert...
Solution:
Given, volume of solution left= 60 mL
Concentration of NaOH=1N
Amount of Cu deposited=31.75 g
Step 1: Calculate the number of moles of NaOH present in the solution left.
n (NaOH) = C (NaOH) x V (solution left)
n (NaOH) = 1 x (60/1000) (1N = 1 mole/L)
n (NaOH) = 0.06 moles
Step 2: Calculate the number of moles of NaCl electrolysed.
NaCl → Na+ + Cl-
The number of moles of NaCl electrolysed= the number of moles of Na+ ions produced.
n (Na+) = 0.06 moles
Step 3: Calculate the amount of NaCl electrolysed.
n (Na+) = n (Cl-)
The number of moles of Cl- ions produced=0.06 moles
The number of moles of NaCl electrolysed=0.06 moles
Molar mass of NaCl= 58.5 g/mol
Mass of NaCl electrolysed= n (NaCl) x Molar mass of NaCl
Mass of NaCl electrolysed= 0.06 x 58.5
Mass of NaCl electrolysed= 3.51 g
Step 4: Calculate the theoretical yield of NaOH.
NaCl + H2O → NaOH + HCl
1 mole of NaCl produces 1 mole of NaOH.
Theoretical yield= 0.06 moles
Step 5: Calculate the percentage yield of NaOH.
Percentage yield = (actual yield/theoretical yield) x 100
Actual yield= mass of NaOH in 60 mL of 1N NaOH solution
Molar mass of NaOH= 40 g/mol
Amount of NaOH= C x V (in L) x Molar mass of NaOH
Amount of NaOH= 1 x (60/1000) x 40
Amount of NaOH= 2.4 g
Percentage yield= (2.4/0.06) x 100
Percentage yield= 400%
Percentage of theoretical yield= 100/400 x 100= 6%
Therefore, the percentage of the theoretical yield of the sodium hydroxide obtained is 6%.
Given, volume of solution left= 60 mL
Concentration of NaOH=1N
Amount of Cu deposited=31.75 g
Step 1: Calculate the number of moles of NaOH present in the solution left.
n (NaOH) = C (NaOH) x V (solution left)
n (NaOH) = 1 x (60/1000) (1N = 1 mole/L)
n (NaOH) = 0.06 moles
Step 2: Calculate the number of moles of NaCl electrolysed.
NaCl → Na+ + Cl-
The number of moles of NaCl electrolysed= the number of moles of Na+ ions produced.
n (Na+) = 0.06 moles
Step 3: Calculate the amount of NaCl electrolysed.
n (Na+) = n (Cl-)
The number of moles of Cl- ions produced=0.06 moles
The number of moles of NaCl electrolysed=0.06 moles
Molar mass of NaCl= 58.5 g/mol
Mass of NaCl electrolysed= n (NaCl) x Molar mass of NaCl
Mass of NaCl electrolysed= 0.06 x 58.5
Mass of NaCl electrolysed= 3.51 g
Step 4: Calculate the theoretical yield of NaOH.
NaCl + H2O → NaOH + HCl
1 mole of NaCl produces 1 mole of NaOH.
Theoretical yield= 0.06 moles
Step 5: Calculate the percentage yield of NaOH.
Percentage yield = (actual yield/theoretical yield) x 100
Actual yield= mass of NaOH in 60 mL of 1N NaOH solution
Molar mass of NaOH= 40 g/mol
Amount of NaOH= C x V (in L) x Molar mass of NaOH
Amount of NaOH= 1 x (60/1000) x 40
Amount of NaOH= 2.4 g
Percentage yield= (2.4/0.06) x 100
Percentage yield= 400%
Percentage of theoretical yield= 100/400 x 100= 6%
Therefore, the percentage of the theoretical yield of the sodium hydroxide obtained is 6%.
Free Test
FREE
| Start Free Test |
Community Answer
After electrolysis of a NaCl solution with inert electrodes for a cert...
6
|
Explore Courses for JEE exam
|
|
Top Courses for JEEView all
Question Description
After electrolysis of a NaCl solution with inert electrodes for a certain period of time, 60 ml of the solution was left which was found to be 1 N in NaOH. During the same time 31.75 g of Cu was deposited in a Cu voltameter in series with the electrolytic cell. Calculate the percentage of the theoretical yield of the sodium hydroxide obtained.a)3b)6c)5d)4Correct answer is '6'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about After electrolysis of a NaCl solution with inert electrodes for a certain period of time, 60 ml of the solution was left which was found to be 1 N in NaOH. During the same time 31.75 g of Cu was deposited in a Cu voltameter in series with the electrolytic cell. Calculate the percentage of the theoretical yield of the sodium hydroxide obtained.a)3b)6c)5d)4Correct answer is '6'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for After electrolysis of a NaCl solution with inert electrodes for a certain period of time, 60 ml of the solution was left which was found to be 1 N in NaOH. During the same time 31.75 g of Cu was deposited in a Cu voltameter in series with the electrolytic cell. Calculate the percentage of the theoretical yield of the sodium hydroxide obtained.a)3b)6c)5d)4Correct answer is '6'. Can you explain this answer?.
After electrolysis of a NaCl solution with inert electrodes for a certain period of time, 60 ml of the solution was left which was found to be 1 N in NaOH. During the same time 31.75 g of Cu was deposited in a Cu voltameter in series with the electrolytic cell. Calculate the percentage of the theoretical yield of the sodium hydroxide obtained.a)3b)6c)5d)4Correct answer is '6'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about After electrolysis of a NaCl solution with inert electrodes for a certain period of time, 60 ml of the solution was left which was found to be 1 N in NaOH. During the same time 31.75 g of Cu was deposited in a Cu voltameter in series with the electrolytic cell. Calculate the percentage of the theoretical yield of the sodium hydroxide obtained.a)3b)6c)5d)4Correct answer is '6'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for After electrolysis of a NaCl solution with inert electrodes for a certain period of time, 60 ml of the solution was left which was found to be 1 N in NaOH. During the same time 31.75 g of Cu was deposited in a Cu voltameter in series with the electrolytic cell. Calculate the percentage of the theoretical yield of the sodium hydroxide obtained.a)3b)6c)5d)4Correct answer is '6'. Can you explain this answer?.
Solutions for After electrolysis of a NaCl solution with inert electrodes for a certain period of time, 60 ml of the solution was left which was found to be 1 N in NaOH. During the same time 31.75 g of Cu was deposited in a Cu voltameter in series with the electrolytic cell. Calculate the percentage of the theoretical yield of the sodium hydroxide obtained.a)3b)6c)5d)4Correct answer is '6'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of After electrolysis of a NaCl solution with inert electrodes for a certain period of time, 60 ml of the solution was left which was found to be 1 N in NaOH. During the same time 31.75 g of Cu was deposited in a Cu voltameter in series with the electrolytic cell. Calculate the percentage of the theoretical yield of the sodium hydroxide obtained.a)3b)6c)5d)4Correct answer is '6'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
After electrolysis of a NaCl solution with inert electrodes for a certain period of time, 60 ml of the solution was left which was found to be 1 N in NaOH. During the same time 31.75 g of Cu was deposited in a Cu voltameter in series with the electrolytic cell. Calculate the percentage of the theoretical yield of the sodium hydroxide obtained.a)3b)6c)5d)4Correct answer is '6'. Can you explain this answer?, a detailed solution for After electrolysis of a NaCl solution with inert electrodes for a certain period of time, 60 ml of the solution was left which was found to be 1 N in NaOH. During the same time 31.75 g of Cu was deposited in a Cu voltameter in series with the electrolytic cell. Calculate the percentage of the theoretical yield of the sodium hydroxide obtained.a)3b)6c)5d)4Correct answer is '6'. Can you explain this answer? has been provided alongside types of After electrolysis of a NaCl solution with inert electrodes for a certain period of time, 60 ml of the solution was left which was found to be 1 N in NaOH. During the same time 31.75 g of Cu was deposited in a Cu voltameter in series with the electrolytic cell. Calculate the percentage of the theoretical yield of the sodium hydroxide obtained.a)3b)6c)5d)4Correct answer is '6'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice After electrolysis of a NaCl solution with inert electrodes for a certain period of time, 60 ml of the solution was left which was found to be 1 N in NaOH. During the same time 31.75 g of Cu was deposited in a Cu voltameter in series with the electrolytic cell. Calculate the percentage of the theoretical yield of the sodium hydroxide obtained.a)3b)6c)5d)4Correct answer is '6'. Can you explain this answer? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup on EduRev and stay on top of your study goals
10M+ students crushing their study goals daily