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derive an expression for the energy stored in a capacitor. show that whenever two conductor share charges by bringing them into electric contact there is a loss of energy
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derive an expression for the energy stored in a capacitor. show that w...
The energy stored in the capacitors can be expressed in terms of work done by the battery. So, the work done to move the charge "dq" from the positive terminal to the negative terminal of the battery is equal to "Vdq" where V is the voltage of the capacitor. This voltage is directly proportional to the current present on the capacitor.Energy store on the capacitor = dU = V.dqEnergy store on the capacitor = Q/C . dq (∵V = Q/C)If "Q" is the amount of charge stored on the capacitor then the total amount of energy on the capacitor is calculated by the integral.Hence,Energy store on the capacitor = U = (integral from 0 to Q) Q/C . dqEnergy store on the capacitor = U = (1/2) . Q�/CThis energy expression can be expressed in three different forms as:U = (1/2) . Q�/CU = (1/2) . QV (∵V = Q/C)U = (1/2) . CV� (∵ Q = CV)Whenever two conductor share charges by bringing them into electrical contact, there is always some amount of loss of energy. Thus energy is scattered in the sharing of charges and is disappeared in the form of heat.
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derive an expression for the energy stored in a capacitor. show that w...
Energy Stored in a Capacitor


When a capacitor is charged, energy is stored in the electric field between its plates. The amount of energy stored in a capacitor can be expressed as:

E = 1/2 CV^2

Where E is the energy stored in joules, C is the capacitance in farads, and V is the voltage across the capacitor in volts.

Loss of Energy When Two Conductors Share Charges


When two conductors share charges by being brought into electric contact, there is a loss of energy due to several factors.

Resistance of the Conductors


When two conductors are brought into contact, there is a finite resistance between them. This resistance causes a voltage drop, which results in a loss of energy. The amount of energy lost due to resistance can be calculated using Ohm's law:

E = I^2Rt

Where E is the energy lost in joules, I is the current flowing through the resistance in amperes, R is the resistance in ohms, and t is the time in seconds.

Heat Generation


When current flows through a resistance, heat is generated due to the Joule heating effect. This heat represents a loss of energy from the system. The amount of heat generated is proportional to the square of the current flowing through the resistance and the resistance itself.

Electromagnetic Radiation


When charges are moved or accelerated, electromagnetic radiation is emitted. This radiation represents a loss of energy from the system. The amount of radiation emitted is proportional to the acceleration of the charges and the square of the frequency of the radiation.

Conclusion


In summary, whenever two conductors share charges by being brought into electric contact, there is a loss of energy due to the resistance of the conductors, heat generation, and electromagnetic radiation. To minimize these losses, it is important to use low-resistance conductors and minimize the amount of time the conductors are in contact.
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derive an expression for the energy stored in a capacitor. show that whenever two conductor share charges by bringing them into electric contact there is a loss of energy
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