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A’ is a substance that converts into B, C and D by three first order parallel paths simultaneously according to the following stoichiometryThe partial t1/2 of A along path I and path II are 173.25 min and 346.5 min respectively. The energies of activation of the reaction along path I, path II and path III are 40, 60 and 80 kJ/mol respectively.The initial rate of consumption of A and the sum of the initial rate of formation of B, C and D arerespectively, taking [A] = 0.25 M, equal toa)2 x 10-3molL-1min-1 and 2.5 x10-3 mol L-1min-1b)2 x 10-3mol L-1min-1 and 2 x10-3 mol L-1min-1c)2.5 x10-3molL-1min-1 and 3 x10-3 mol L-1min-1d)4 x10-3molL-1min-1 and 2 x 10-3 mol L-1min-1Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A’ is a substance that converts into B, C and D by three first order parallel paths simultaneously according to the following stoichiometryThe partial t1/2 of A along path I and path II are 173.25 min and 346.5 min respectively. The energies of activation of the reaction along path I, path II and path III are 40, 60 and 80 kJ/mol respectively.The initial rate of consumption of A and the sum of the initial rate of formation of B, C and D arerespectively, taking [A] = 0.25 M, equal toa)2 x 10-3molL-1min-1 and 2.5 x10-3 mol L-1min-1b)2 x 10-3mol L-1min-1 and 2 x10-3 mol L-1min-1c)2.5 x10-3molL-1min-1 and 3 x10-3 mol L-1min-1d)4 x10-3molL-1min-1 and 2 x 10-3 mol L-1min-1Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A’ is a substance that converts into B, C and D by three first order parallel paths simultaneously according to the following stoichiometryThe partial t1/2 of A along path I and path II are 173.25 min and 346.5 min respectively. The energies of activation of the reaction along path I, path II and path III are 40, 60 and 80 kJ/mol respectively.The initial rate of consumption of A and the sum of the initial rate of formation of B, C and D arerespectively, taking [A] = 0.25 M, equal toa)2 x 10-3molL-1min-1 and 2.5 x10-3 mol L-1min-1b)2 x 10-3mol L-1min-1 and 2 x10-3 mol L-1min-1c)2.5 x10-3molL-1min-1 and 3 x10-3 mol L-1min-1d)4 x10-3molL-1min-1 and 2 x 10-3 mol L-1min-1Correct answer is option 'A'. Can you explain this answer?.

Solutions for A’ is a substance that converts into B, C and D by three first order parallel paths simultaneously according to the following stoichiometryThe partial t1/2 of A along path I and path II are 173.25 min and 346.5 min respectively. The energies of activation of the reaction along path I, path II and path III are 40, 60 and 80 kJ/mol respectively.The initial rate of consumption of A and the sum of the initial rate of formation of B, C and D arerespectively, taking [A] = 0.25 M, equal toa)2 x 10-3molL-1min-1 and 2.5 x10-3 mol L-1min-1b)2 x 10-3mol L-1min-1 and 2 x10-3 mol L-1min-1c)2.5 x10-3molL-1min-1 and 3 x10-3 mol L-1min-1d)4 x10-3molL-1min-1 and 2 x 10-3 mol L-1min-1Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of A’ is a substance that converts into B, C and D by three first order parallel paths simultaneously according to the following stoichiometryThe partial t1/2 of A along path I and path II are 173.25 min and 346.5 min respectively. The energies of activation of the reaction along path I, path II and path III are 40, 60 and 80 kJ/mol respectively.The initial rate of consumption of A and the sum of the initial rate of formation of B, C and D arerespectively, taking [A] = 0.25 M, equal toa)2 x 10-3molL-1min-1 and 2.5 x10-3 mol L-1min-1b)2 x 10-3mol L-1min-1 and 2 x10-3 mol L-1min-1c)2.5 x10-3molL-1min-1 and 3 x10-3 mol L-1min-1d)4 x10-3molL-1min-1 and 2 x 10-3 mol L-1min-1Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A’ is a substance that converts into B, C and D by three first order parallel paths simultaneously according to the following stoichiometryThe partial t1/2 of A along path I and path II are 173.25 min and 346.5 min respectively. The energies of activation of the reaction along path I, path II and path III are 40, 60 and 80 kJ/mol respectively.The initial rate of consumption of A and the sum of the initial rate of formation of B, C and D arerespectively, taking [A] = 0.25 M, equal toa)2 x 10-3molL-1min-1 and 2.5 x10-3 mol L-1min-1b)2 x 10-3mol L-1min-1 and 2 x10-3 mol L-1min-1c)2.5 x10-3molL-1min-1 and 3 x10-3 mol L-1min-1d)4 x10-3molL-1min-1 and 2 x 10-3 mol L-1min-1Correct answer is option 'A'. Can you explain this answer?, a detailed solution for A’ is a substance that converts into B, C and D by three first order parallel paths simultaneously according to the following stoichiometryThe partial t1/2 of A along path I and path II are 173.25 min and 346.5 min respectively. The energies of activation of the reaction along path I, path II and path III are 40, 60 and 80 kJ/mol respectively.The initial rate of consumption of A and the sum of the initial rate of formation of B, C and D arerespectively, taking [A] = 0.25 M, equal toa)2 x 10-3molL-1min-1 and 2.5 x10-3 mol L-1min-1b)2 x 10-3mol L-1min-1 and 2 x10-3 mol L-1min-1c)2.5 x10-3molL-1min-1 and 3 x10-3 mol L-1min-1d)4 x10-3molL-1min-1 and 2 x 10-3 mol L-1min-1Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of A’ is a substance that converts into B, C and D by three first order parallel paths simultaneously according to the following stoichiometryThe partial t1/2 of A along path I and path II are 173.25 min and 346.5 min respectively. The energies of activation of the reaction along path I, path II and path III are 40, 60 and 80 kJ/mol respectively.The initial rate of consumption of A and the sum of the initial rate of formation of B, C and D arerespectively, taking [A] = 0.25 M, equal toa)2 x 10-3molL-1min-1 and 2.5 x10-3 mol L-1min-1b)2 x 10-3mol L-1min-1 and 2 x10-3 mol L-1min-1c)2.5 x10-3molL-1min-1 and 3 x10-3 mol L-1min-1d)4 x10-3molL-1min-1 and 2 x 10-3 mol L-1min-1Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A’ is a substance that converts into B, C and D by three first order parallel paths simultaneously according to the following stoichiometryThe partial t1/2 of A along path I and path II are 173.25 min and 346.5 min respectively. The energies of activation of the reaction along path I, path II and path III are 40, 60 and 80 kJ/mol respectively.The initial rate of consumption of A and the sum of the initial rate of formation of B, C and D arerespectively, taking [A] = 0.25 M, equal toa)2 x 10-3molL-1min-1 and 2.5 x10-3 mol L-1min-1b)2 x 10-3mol L-1min-1 and 2 x10-3 mol L-1min-1c)2.5 x10-3molL-1min-1 and 3 x10-3 mol L-1min-1d)4 x10-3molL-1min-1 and 2 x 10-3 mol L-1min-1Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.