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There are two companies X and Y having m and n employees respectively. If an employee ‘A’ from company X knows an employee ‘B’ from company Y, then B is termed to be an acquaintance of A. In all there are exactly 1024 ways in which acquaintances can be formed. How many ordered pairs of (m, n) are possible?
- a)5
- b)4
- c)3
- d)None of the above.
Correct answer is option 'B'. Can you explain this answer?
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There are two companies X and Y having m and n employees respectively....
Solution: The question means that there are m elements in set X and n elements in set Y. The total number of each element of Y can have multiple employees of X as acquaintances.
Thus, this is similar to the problem of sending r students to p classrooms which can be done in rp ways.
Thus, m elements of set X have mn acquaintances.
mn = 1024. (m, n) = (1024, 1); (2, 10); (4, 5); (32, 2) Hence, option 2.
Thus, this is similar to the problem of sending r students to p classrooms which can be done in rp ways.
Thus, m elements of set X have mn acquaintances.
mn = 1024. (m, n) = (1024, 1); (2, 10); (4, 5); (32, 2) Hence, option 2.
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There are two companies X and Y having m and n employees respectively. If an employee A from company X knows an employee B from company Y, then B is termed to be an acquaintance of A. In all there are exactly 1024 ways in which acquaintances can be formed. How many ordered pairs of (m, n) are possible?a)5b)4c)3d)None of the above.Correct answer is option 'B'. Can you explain this answer?
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