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If tan3θ + tanθ = 2tan2θ then θ is equal to (n ∈ z)
  • a)
  • b)
    nπ/4
  • c)
    2nπ
  • d)
    none of these
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
If tan3 + tan = 2tan2 then is equal to (n z)a)nb)n/4c)2nd)none of th...
θ = nπ,n ∈ z or 2θ = nπ ∵  θ = nπ/2  is not for possible as n is odd tanθ is not define.
Hence θ = nπ, n ∈ z is the only solution.
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If tan3 + tan = 2tan2 then is equal to (n z)a)nb)n/4c)2nd)none of theseCorrect answer is option 'A'. Can you explain this answer?
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