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The Bertholet’s equation of state for 1 mole real gas is given as under:Where a and b are van der Waal’s constants. van der Waal’s constant “a” signifies, the force of attractionamong the gas molecules. van der Waal’s constant “b” signifies incompressible volume i.e. volumehaving no effect of compression and expansion. It is also known as co-volume. Thereby the volumehaving effect of compression and expansion i.e. compressible volume = V – b (for 1 mole real gas).One of the form of van der Waal’s equation of state is virial equation. The virial equation for 1 mole realgas is as under:where A, B, C are known as 2nd, 3rd and 4th virial coefficients respectively. The temperature at which real gases obey ideal gas equation (PV = RT), is known as Boyles temperature i.e. TB.Q.If the third virial coefficient of 4 moles of mono-atomic as is 0.04 (lit/mol)2 at NTP, then what will be the real gas at NTP?a)88.8 litersb)80 litersc)89 litersd)90.4 litersCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The Bertholet’s equation of state for 1 mole real gas is given as under:Where a and b are van der Waal’s constants. van der Waal’s constant “a” signifies, the force of attractionamong the gas molecules. van der Waal’s constant “b” signifies incompressible volume i.e. volumehaving no effect of compression and expansion. It is also known as co-volume. Thereby the volumehaving effect of compression and expansion i.e. compressible volume = V – b (for 1 mole real gas).One of the form of van der Waal’s equation of state is virial equation. The virial equation for 1 mole realgas is as under:where A, B, C are known as 2nd, 3rd and 4th virial coefficients respectively. The temperature at which real gases obey ideal gas equation (PV = RT), is known as Boyles temperature i.e. TB.Q.If the third virial coefficient of 4 moles of mono-atomic as is 0.04 (lit/mol)2 at NTP, then what will be the real gas at NTP?a)88.8 litersb)80 litersc)89 litersd)90.4 litersCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The Bertholet’s equation of state for 1 mole real gas is given as under:Where a and b are van der Waal’s constants. van der Waal’s constant “a” signifies, the force of attractionamong the gas molecules. van der Waal’s constant “b” signifies incompressible volume i.e. volumehaving no effect of compression and expansion. It is also known as co-volume. Thereby the volumehaving effect of compression and expansion i.e. compressible volume = V – b (for 1 mole real gas).One of the form of van der Waal’s equation of state is virial equation. The virial equation for 1 mole realgas is as under:where A, B, C are known as 2nd, 3rd and 4th virial coefficients respectively. The temperature at which real gases obey ideal gas equation (PV = RT), is known as Boyles temperature i.e. TB.Q.If the third virial coefficient of 4 moles of mono-atomic as is 0.04 (lit/mol)2 at NTP, then what will be the real gas at NTP?a)88.8 litersb)80 litersc)89 litersd)90.4 litersCorrect answer is option 'D'. Can you explain this answer?.

Solutions for The Bertholet’s equation of state for 1 mole real gas is given as under:Where a and b are van der Waal’s constants. van der Waal’s constant “a” signifies, the force of attractionamong the gas molecules. van der Waal’s constant “b” signifies incompressible volume i.e. volumehaving no effect of compression and expansion. It is also known as co-volume. Thereby the volumehaving effect of compression and expansion i.e. compressible volume = V – b (for 1 mole real gas).One of the form of van der Waal’s equation of state is virial equation. The virial equation for 1 mole realgas is as under:where A, B, C are known as 2nd, 3rd and 4th virial coefficients respectively. The temperature at which real gases obey ideal gas equation (PV = RT), is known as Boyles temperature i.e. TB.Q.If the third virial coefficient of 4 moles of mono-atomic as is 0.04 (lit/mol)2 at NTP, then what will be the real gas at NTP?a)88.8 litersb)80 litersc)89 litersd)90.4 litersCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of The Bertholet’s equation of state for 1 mole real gas is given as under:Where a and b are van der Waal’s constants. van der Waal’s constant “a” signifies, the force of attractionamong the gas molecules. van der Waal’s constant “b” signifies incompressible volume i.e. volumehaving no effect of compression and expansion. It is also known as co-volume. Thereby the volumehaving effect of compression and expansion i.e. compressible volume = V – b (for 1 mole real gas).One of the form of van der Waal’s equation of state is virial equation. The virial equation for 1 mole realgas is as under:where A, B, C are known as 2nd, 3rd and 4th virial coefficients respectively. The temperature at which real gases obey ideal gas equation (PV = RT), is known as Boyles temperature i.e. TB.Q.If the third virial coefficient of 4 moles of mono-atomic as is 0.04 (lit/mol)2 at NTP, then what will be the real gas at NTP?a)88.8 litersb)80 litersc)89 litersd)90.4 litersCorrect answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The Bertholet’s equation of state for 1 mole real gas is given as under:Where a and b are van der Waal’s constants. van der Waal’s constant “a” signifies, the force of attractionamong the gas molecules. van der Waal’s constant “b” signifies incompressible volume i.e. volumehaving no effect of compression and expansion. It is also known as co-volume. Thereby the volumehaving effect of compression and expansion i.e. compressible volume = V – b (for 1 mole real gas).One of the form of van der Waal’s equation of state is virial equation. The virial equation for 1 mole realgas is as under:where A, B, C are known as 2nd, 3rd and 4th virial coefficients respectively. The temperature at which real gases obey ideal gas equation (PV = RT), is known as Boyles temperature i.e. TB.Q.If the third virial coefficient of 4 moles of mono-atomic as is 0.04 (lit/mol)2 at NTP, then what will be the real gas at NTP?a)88.8 litersb)80 litersc)89 litersd)90.4 litersCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for The Bertholet’s equation of state for 1 mole real gas is given as under:Where a and b are van der Waal’s constants. van der Waal’s constant “a” signifies, the force of attractionamong the gas molecules. van der Waal’s constant “b” signifies incompressible volume i.e. volumehaving no effect of compression and expansion. It is also known as co-volume. Thereby the volumehaving effect of compression and expansion i.e. compressible volume = V – b (for 1 mole real gas).One of the form of van der Waal’s equation of state is virial equation. The virial equation for 1 mole realgas is as under:where A, B, C are known as 2nd, 3rd and 4th virial coefficients respectively. The temperature at which real gases obey ideal gas equation (PV = RT), is known as Boyles temperature i.e. TB.Q.If the third virial coefficient of 4 moles of mono-atomic as is 0.04 (lit/mol)2 at NTP, then what will be the real gas at NTP?a)88.8 litersb)80 litersc)89 litersd)90.4 litersCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of The Bertholet’s equation of state for 1 mole real gas is given as under:Where a and b are van der Waal’s constants. van der Waal’s constant “a” signifies, the force of attractionamong the gas molecules. van der Waal’s constant “b” signifies incompressible volume i.e. volumehaving no effect of compression and expansion. It is also known as co-volume. Thereby the volumehaving effect of compression and expansion i.e. compressible volume = V – b (for 1 mole real gas).One of the form of van der Waal’s equation of state is virial equation. The virial equation for 1 mole realgas is as under:where A, B, C are known as 2nd, 3rd and 4th virial coefficients respectively. The temperature at which real gases obey ideal gas equation (PV = RT), is known as Boyles temperature i.e. TB.Q.If the third virial coefficient of 4 moles of mono-atomic as is 0.04 (lit/mol)2 at NTP, then what will be the real gas at NTP?a)88.8 litersb)80 litersc)89 litersd)90.4 litersCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The Bertholet’s equation of state for 1 mole real gas is given as under:Where a and b are van der Waal’s constants. van der Waal’s constant “a” signifies, the force of attractionamong the gas molecules. van der Waal’s constant “b” signifies incompressible volume i.e. volumehaving no effect of compression and expansion. It is also known as co-volume. Thereby the volumehaving effect of compression and expansion i.e. compressible volume = V – b (for 1 mole real gas).One of the form of van der Waal’s equation of state is virial equation. The virial equation for 1 mole realgas is as under:where A, B, C are known as 2nd, 3rd and 4th virial coefficients respectively. The temperature at which real gases obey ideal gas equation (PV = RT), is known as Boyles temperature i.e. TB.Q.If the third virial coefficient of 4 moles of mono-atomic as is 0.04 (lit/mol)2 at NTP, then what will be the real gas at NTP?a)88.8 litersb)80 litersc)89 litersd)90.4 litersCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice JEE tests.