A circuit shown in the figure consists of a battery of emf 10V and two capacitance C1 and C2 of capacitances 1.0mF and 2.0mF respectively. The potential difference VA _ VB is 5Va)charge on capacitor C1 is equal to charge on capacitor C2b)Voltage across capacitor C1 is 5Vc)Voltage across capacitor C2 is 10 Vd)Energy stored in capacitor C1 is two times the energy stored in capacitor C2Correct answer is option 'A,D'. Can you explain this answer?

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A circuit shown in the figure consists of a battery of emf 10V and two capacitance C₁and C₂ of capacitances 1.0mF and 2.0mF respectively. The potential difference V_A ^_ V_B is 5V

a)
charge on capacitor C₁ is equal to charge on capacitor C₂
b)
Voltage across capacitor C₁ is 5V
c)
Voltage across capacitor C₂ is 10 V
d)
Energy stored in capacitor C₁ is two times the energy stored in capacitor C₂

Correct answer is option 'A,D'. Can you explain this answer?

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A circuit shown in the figure consists of a battery of emf 10V and two...

Here the capacitors are in series so the charge on each is equal to equivalent charge.
The equivalent capacitance is Ceq=(1×2)/(1+2) =(2/3)μF and the equivalent charge , Q_eq=C_eqV=(2/3)(10+5)=10μC
Thus, Q₁=Q₂=Q_eq=10μC
Potential across C1 is V1=Q1/C1=10/1=10V and Potential across C₂ is V₂=Q₂/C₂=10/2=5V

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A circuit shown in the figure consists of a battery of emf 10V and two capacitance C1 and C2 of capacitances 1.0mF and 2.0mF respectively. The potential difference VA _ VB is 5Va)charge on capacitor C1 is equal to charge on capacitor C2b)Voltage across capacitor C1 is 5Vc)Voltage across capacitor C2 is 10 Vd)Energy stored in capacitor C1 is two times the energy stored in capacitor C2Correct answer is option 'A,D'. Can you explain this answer?

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