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An alternating current of frequency 200 rad/sec and peak value 1 A as shown in the figure, is applied to the primary of a transformer. If the coefficient of mutual induction between the primary and the secondary is 1.5 H, the voltage induced in the secondary will be Ans is 191 v?
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An alternating current of frequency 200 rad/sec and peak value 1 A as ...
Calculation of Secondary Voltage in Transformer
1. Given Data:
- Frequency of alternating current (f) = 200 rad/sec
- Peak value of current in primary (Ip) = 1 A
- Coefficient of mutual induction (M) = 1.5 H
2. Formula for Voltage Induced:
- The formula for voltage induced in the secondary of a transformer is given by:
Vs = M * w * Ip
where,
Vs = Voltage induced in the secondary
M = Coefficient of mutual induction
w = Angular frequency (2πf)
Ip = Peak value of current in primary
3. Calculations:
- Angular frequency, w = 2π * f = 2π * 200 = 400π rad/sec
- Substituting the values in the formula:
Vs = 1.5 * 400π * 1
Vs = 600π V
Vs ≈ 1885.44 V
4. Conclusion:
- The voltage induced in the secondary of the transformer is approximately 1885.44 V.
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A thermal power plant produces electric power of 600 kW at 4000 V, which is to be transported to a place 20 km away from the power plant for consumers usage. It can be transported either directly with a cable of large current carrying capacity or by using a combination of step-up and step-down transformers at the two ends. The drawback of the direct transmission is the large energy dissipation. In the method using transformers, the dissipation is much smaller. In this method , a step-up transformer is used at theplant side so that the current is reduced to a smaller value. At the consumers end, a step-down transformer is used to supply power to the consumers at the specified lower voltage. It is reasonable to assume that the power cable is purely resistive and the transformers are ideal with power factor unity. All the currents and voltages mentioned are rms values.Q.In the method using the transformers, assume that the ratio of the number of turns in the primary to that in the secondary in the step-up transformer is 1 : 10. If the power to the consumers has to be supplied at 200 V, the ratio of the number of turns in the primary to that in the secondary in the stepdown transformer is

ParagraphA thermal power plant produces electric power of 600 kW at 4000 V, which is to be transported to a place 20 km away from the power plant for consumers’ usage. It can be transported either directly with a cable of large current carrying capacity or by using a combination of step-up and step-down transformers at the two ends. The drawback of the direct transmission is the large energy dissipation. In the method using transformers, the dissipation is much smaller. In this method, a step-up transformer is used at the plant side so that the current is reduced to a smaller value. At the consumers’ end, a step-down transformer is used to supply power to the consumers at the specified lower voltage. It is reasonable to assume that the power cable is purely resistive and the transformers are ideal with the power factor unity. All the currents and voltage mentioned are rms values.Q.In the method using the transformers, assume that the ratio of the number of turns in the primary to that inthe secondary in the step-up transformer is 1 : 10. If the power to the consumers has to be supplied at200 V, the ratio of the number of turns in the primary to that in the secondary in the step-down transformeris

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An alternating current of frequency 200 rad/sec and peak value 1 A as shown in the figure, is applied to the primary of a transformer. If the coefficient of mutual induction between the primary and the secondary is 1.5 H, the voltage induced in the secondary will be Ans is 191 v?
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An alternating current of frequency 200 rad/sec and peak value 1 A as shown in the figure, is applied to the primary of a transformer. If the coefficient of mutual induction between the primary and the secondary is 1.5 H, the voltage induced in the secondary will be Ans is 191 v? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An alternating current of frequency 200 rad/sec and peak value 1 A as shown in the figure, is applied to the primary of a transformer. If the coefficient of mutual induction between the primary and the secondary is 1.5 H, the voltage induced in the secondary will be Ans is 191 v? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An alternating current of frequency 200 rad/sec and peak value 1 A as shown in the figure, is applied to the primary of a transformer. If the coefficient of mutual induction between the primary and the secondary is 1.5 H, the voltage induced in the secondary will be Ans is 191 v?.
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