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Positive and negative point charges of equal magnitude are kept at locations ( 0,0,a/2) and (0,0,-a/2) respectively. The work done by the electric field when another positive point charge is moved from (-a,0,0) to (0,a,0) is
- a)depends on the path connecting the initial and final positions
- b)positive
- c)negative
- d)Zero
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
Positive and negative point charges of equal magnitude are kept at loc...
+Q charge is moving on equatorial line of dipole as shown in figure, since on equatorial line V=0,
Hence the potential difference is zero. So, W=0
Hence the potential difference is zero. So, W=0
Most Upvoted Answer
Positive and negative point charges of equal magnitude are kept at loc...
Work Done by Electric Field in Moving a Charge
The work done by the electric field in moving a point charge from one position to another can be calculated using the formula:
W = -ΔU
where W is the work done, ΔU is the change in potential energy of the system.
Given:
- Positive and negative point charges of equal magnitude are kept at locations (0,0,a/2) and (0,0,-a/2) respectively.
- Another positive point charge is moved from (-a,0,0) to (0,a,0).
Since the charge being moved is positive, it will experience a force in the direction of the negative charge and against the direction of the positive charge. As the charge moves closer to the negative charge, the potential energy of the system decreases as the charges get closer. Similarly, as the charge moves away from the positive charge, the potential energy of the system increases. At the end of the motion, the charge is equidistant from the two charges and the potential energy of the system is the same as its initial value.
Therefore, the change in potential energy of the system is zero, which means the work done by the electric field is also zero. This is independent of the path taken by the charge and hence the correct option is (D) Zero.
The work done by the electric field in moving a point charge from one position to another can be calculated using the formula:
W = -ΔU
where W is the work done, ΔU is the change in potential energy of the system.
Given:
- Positive and negative point charges of equal magnitude are kept at locations (0,0,a/2) and (0,0,-a/2) respectively.
- Another positive point charge is moved from (-a,0,0) to (0,a,0).
Since the charge being moved is positive, it will experience a force in the direction of the negative charge and against the direction of the positive charge. As the charge moves closer to the negative charge, the potential energy of the system decreases as the charges get closer. Similarly, as the charge moves away from the positive charge, the potential energy of the system increases. At the end of the motion, the charge is equidistant from the two charges and the potential energy of the system is the same as its initial value.
Therefore, the change in potential energy of the system is zero, which means the work done by the electric field is also zero. This is independent of the path taken by the charge and hence the correct option is (D) Zero.
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Community Answer
Positive and negative point charges of equal magnitude are kept at loc...
The charge is moving on equatorial plane thus potential is zero therefore work done is also zero
Thus option D
Thus option D
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Positive and negative point charges of equal magnitude are kept at locations ( 0,0,a/2) and (0,0,-a/2) respectively. The work done by the electric field when another positive point charge is moved from (-a,0,0) to (0,a,0) isa)depends on the path connecting the initial and final positionsb)positivec)negatived)ZeroCorrect answer is option 'D'. Can you explain this answer?
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