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The ionic radii of A+ and B- ions are 0.98 x 10-10 m and 1.81 x10-10 m. The coordination number of each ions in AB is
- a)4
- b)8
- c)2
- d)6
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The ionic radii of A+and B-ions are 0.98 x 10-10m and 1.81 x10-10m. Th...
Given, ionic radius of cation (A+) =0.98 x 10-10m
Ionic radius of anion (B-)=1.81 x 10-10m
therefore,
The coordination number of each ion in AB =?
Now we have.
Ionic radius of anion (B-)=1.81 x 10-10m
therefore,
The coordination number of each ion in AB =?
Now we have.
If radius ratio range is in between 0.441-0.732 ion would have an octahedral structure with coordination number six.Most Upvoted Answer
The ionic radii of A+and B-ions are 0.98 x 10-10m and 1.81 x10-10m. Th...
Calculation of Coordination Number in AB
Definition: The coordination number is defined as the number of ions or atoms immediately surrounding a central ion or atom.
Given,
Ionic radii of A-ion = 0.98 x 10^-10m
Ionic radii of B-ion = 1.81 x 10^-10m
To calculate the coordination number of ions A and B in AB, we need to use the concept of ionic radii and lattice structure.
Lattice Structure: The lattice structure is the arrangement of ions or atoms in a crystal lattice. It can be either a simple cubic, body-centered cubic, or face-centered cubic.
Calculation:
1. We know that the sum of the ionic radii of A and B-ions in AB should be equal to the distance between them.
Sum of ionic radii of A and B-ions = radius of A-ion + radius of B-ion
= 0.98 x 10^-10m + 1.81 x 10^-10m
= 2.79 x 10^-10m
2. We can assume that the lattice structure of AB is face-centered cubic (FCC).
In FCC, the distance between the centers of the two ions is given by,
√2 × rB
where rB is the radius of B-ion.
Distance between A and B ions = √2 × rB
= √2 × 1.81 x 10^-10m
= 2.56 x 10^-10m
3. Now, we can calculate the coordination number of A and B-ions in AB using the formula,
Coordination number = 4 × (radius of A-ion / distance between A and B ions)^2
Coordination number of A-ion = 4 × (0.98 x 10^-10m / 2.56 x 10^-10m)^2
= 6
Coordination number of B-ion = 4 × (1.81 x 10^-10m / 2.56 x 10^-10m)^2
= 6
Conclusion: Therefore, the coordination number of each ion in AB is 6.
Definition: The coordination number is defined as the number of ions or atoms immediately surrounding a central ion or atom.
Given,
Ionic radii of A-ion = 0.98 x 10^-10m
Ionic radii of B-ion = 1.81 x 10^-10m
To calculate the coordination number of ions A and B in AB, we need to use the concept of ionic radii and lattice structure.
Lattice Structure: The lattice structure is the arrangement of ions or atoms in a crystal lattice. It can be either a simple cubic, body-centered cubic, or face-centered cubic.
Calculation:
1. We know that the sum of the ionic radii of A and B-ions in AB should be equal to the distance between them.
Sum of ionic radii of A and B-ions = radius of A-ion + radius of B-ion
= 0.98 x 10^-10m + 1.81 x 10^-10m
= 2.79 x 10^-10m
2. We can assume that the lattice structure of AB is face-centered cubic (FCC).
In FCC, the distance between the centers of the two ions is given by,
√2 × rB
where rB is the radius of B-ion.
Distance between A and B ions = √2 × rB
= √2 × 1.81 x 10^-10m
= 2.56 x 10^-10m
3. Now, we can calculate the coordination number of A and B-ions in AB using the formula,
Coordination number = 4 × (radius of A-ion / distance between A and B ions)^2
Coordination number of A-ion = 4 × (0.98 x 10^-10m / 2.56 x 10^-10m)^2
= 6
Coordination number of B-ion = 4 × (1.81 x 10^-10m / 2.56 x 10^-10m)^2
= 6
Conclusion: Therefore, the coordination number of each ion in AB is 6.
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The ionic radii of A+and B-ions are 0.98 x 10-10m and 1.81 x10-10m. The coordination number of each ions in AB isa)4b)8c)2d)6Correct answer is option 'D'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The ionic radii of A+and B-ions are 0.98 x 10-10m and 1.81 x10-10m. The coordination number of each ions in AB isa)4b)8c)2d)6Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The ionic radii of A+and B-ions are 0.98 x 10-10m and 1.81 x10-10m. The coordination number of each ions in AB isa)4b)8c)2d)6Correct answer is option 'D'. Can you explain this answer?.
The ionic radii of A+and B-ions are 0.98 x 10-10m and 1.81 x10-10m. The coordination number of each ions in AB isa)4b)8c)2d)6Correct answer is option 'D'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The ionic radii of A+and B-ions are 0.98 x 10-10m and 1.81 x10-10m. The coordination number of each ions in AB isa)4b)8c)2d)6Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The ionic radii of A+and B-ions are 0.98 x 10-10m and 1.81 x10-10m. The coordination number of each ions in AB isa)4b)8c)2d)6Correct answer is option 'D'. Can you explain this answer?.
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