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We know that balancing of a chemical equation is entirely based on law of conservation of mass. However the concept of Principle of Atom Conservation (POAC) can also be related to law of conservation of mass in a chemical reaction. So, POAC can also act as a technique for balancing a chemical equation. For example, for a reaction
ABC3 → AB + C2
0n applying POAC for, B & C and relating the 3 equations, we get : ( nx :  number of 
moles of X) Thus, the coefficients of ABC3 , AB & C2 in the balanced chemical equation will be 2,2 & 3 respectively and the balanced chemical equation can be represented as
2ABC3 → 2AB + 3C2
Now answer the following questions :
 
Q.
If the atomic masses of X and Y are 10 & 30 respectivetly, then the mass of XY3 formed when 120g of Y2 reacts completely with X is : Reaction X + Y2 ¾¾® XY3
  • a)
    133.3 g
  • b)
    200 g
  • c)
    266.6 g
  • d)
    400 g
Correct answer is option 'A'. Can you explain this answer?
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We know that balancing of a chemical equation is entirely based on law of conservation of mass. However the concept of Principle of Atom Conservation (POAC) can also be related to law of conservation of mass in a chemical reaction. So, POAC can also act as a technique for balancing achemical equation. For example, for a reactionABC3 → AB + C20n applying POAC for, B & C and relating the 3 equations, we get : ( nx : number ofmoles of X) Thus, the coefficients of ABC3 , AB & C2 in the balanced chemical equation will be 2,2 & 3 respectively and the balanced chemical equation can be represented as2ABC3 → 2AB + 3C2Now answer the following questions :Q.If the atomic masses of X and Y are 10 & 30 respectivetly, then the mass of XY3 formed when 120g of Y2 reacts completely with X is : Reaction X + Y2 ¾¾® XY3a)133.3 gb)200 gc)266.6 gd)400 gCorrect answer is option 'A'. Can you explain this answer?
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We know that balancing of a chemical equation is entirely based on law of conservation of mass. However the concept of Principle of Atom Conservation (POAC) can also be related to law of conservation of mass in a chemical reaction. So, POAC can also act as a technique for balancing achemical equation. For example, for a reactionABC3 → AB + C20n applying POAC for, B & C and relating the 3 equations, we get : ( nx : number ofmoles of X) Thus, the coefficients of ABC3 , AB & C2 in the balanced chemical equation will be 2,2 & 3 respectively and the balanced chemical equation can be represented as2ABC3 → 2AB + 3C2Now answer the following questions :Q.If the atomic masses of X and Y are 10 & 30 respectivetly, then the mass of XY3 formed when 120g of Y2 reacts completely with X is : Reaction X + Y2 ¾¾® XY3a)133.3 gb)200 gc)266.6 gd)400 gCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about We know that balancing of a chemical equation is entirely based on law of conservation of mass. However the concept of Principle of Atom Conservation (POAC) can also be related to law of conservation of mass in a chemical reaction. So, POAC can also act as a technique for balancing achemical equation. For example, for a reactionABC3 → AB + C20n applying POAC for, B & C and relating the 3 equations, we get : ( nx : number ofmoles of X) Thus, the coefficients of ABC3 , AB & C2 in the balanced chemical equation will be 2,2 & 3 respectively and the balanced chemical equation can be represented as2ABC3 → 2AB + 3C2Now answer the following questions :Q.If the atomic masses of X and Y are 10 & 30 respectivetly, then the mass of XY3 formed when 120g of Y2 reacts completely with X is : Reaction X + Y2 ¾¾® XY3a)133.3 gb)200 gc)266.6 gd)400 gCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for We know that balancing of a chemical equation is entirely based on law of conservation of mass. However the concept of Principle of Atom Conservation (POAC) can also be related to law of conservation of mass in a chemical reaction. So, POAC can also act as a technique for balancing achemical equation. For example, for a reactionABC3 → AB + C20n applying POAC for, B & C and relating the 3 equations, we get : ( nx : number ofmoles of X) Thus, the coefficients of ABC3 , AB & C2 in the balanced chemical equation will be 2,2 & 3 respectively and the balanced chemical equation can be represented as2ABC3 → 2AB + 3C2Now answer the following questions :Q.If the atomic masses of X and Y are 10 & 30 respectivetly, then the mass of XY3 formed when 120g of Y2 reacts completely with X is : Reaction X + Y2 ¾¾® XY3a)133.3 gb)200 gc)266.6 gd)400 gCorrect answer is option 'A'. Can you explain this answer?.
Solutions for We know that balancing of a chemical equation is entirely based on law of conservation of mass. However the concept of Principle of Atom Conservation (POAC) can also be related to law of conservation of mass in a chemical reaction. So, POAC can also act as a technique for balancing achemical equation. For example, for a reactionABC3 → AB + C20n applying POAC for, B & C and relating the 3 equations, we get : ( nx : number ofmoles of X) Thus, the coefficients of ABC3 , AB & C2 in the balanced chemical equation will be 2,2 & 3 respectively and the balanced chemical equation can be represented as2ABC3 → 2AB + 3C2Now answer the following questions :Q.If the atomic masses of X and Y are 10 & 30 respectivetly, then the mass of XY3 formed when 120g of Y2 reacts completely with X is : Reaction X + Y2 ¾¾® XY3a)133.3 gb)200 gc)266.6 gd)400 gCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of We know that balancing of a chemical equation is entirely based on law of conservation of mass. However the concept of Principle of Atom Conservation (POAC) can also be related to law of conservation of mass in a chemical reaction. So, POAC can also act as a technique for balancing achemical equation. For example, for a reactionABC3 → AB + C20n applying POAC for, B & C and relating the 3 equations, we get : ( nx : number ofmoles of X) Thus, the coefficients of ABC3 , AB & C2 in the balanced chemical equation will be 2,2 & 3 respectively and the balanced chemical equation can be represented as2ABC3 → 2AB + 3C2Now answer the following questions :Q.If the atomic masses of X and Y are 10 & 30 respectivetly, then the mass of XY3 formed when 120g of Y2 reacts completely with X is : Reaction X + Y2 ¾¾® XY3a)133.3 gb)200 gc)266.6 gd)400 gCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of We know that balancing of a chemical equation is entirely based on law of conservation of mass. However the concept of Principle of Atom Conservation (POAC) can also be related to law of conservation of mass in a chemical reaction. So, POAC can also act as a technique for balancing achemical equation. For example, for a reactionABC3 → AB + C20n applying POAC for, B & C and relating the 3 equations, we get : ( nx : number ofmoles of X) Thus, the coefficients of ABC3 , AB & C2 in the balanced chemical equation will be 2,2 & 3 respectively and the balanced chemical equation can be represented as2ABC3 → 2AB + 3C2Now answer the following questions :Q.If the atomic masses of X and Y are 10 & 30 respectivetly, then the mass of XY3 formed when 120g of Y2 reacts completely with X is : Reaction X + Y2 ¾¾® XY3a)133.3 gb)200 gc)266.6 gd)400 gCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for We know that balancing of a chemical equation is entirely based on law of conservation of mass. However the concept of Principle of Atom Conservation (POAC) can also be related to law of conservation of mass in a chemical reaction. So, POAC can also act as a technique for balancing achemical equation. For example, for a reactionABC3 → AB + C20n applying POAC for, B & C and relating the 3 equations, we get : ( nx : number ofmoles of X) Thus, the coefficients of ABC3 , AB & C2 in the balanced chemical equation will be 2,2 & 3 respectively and the balanced chemical equation can be represented as2ABC3 → 2AB + 3C2Now answer the following questions :Q.If the atomic masses of X and Y are 10 & 30 respectivetly, then the mass of XY3 formed when 120g of Y2 reacts completely with X is : Reaction X + Y2 ¾¾® XY3a)133.3 gb)200 gc)266.6 gd)400 gCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of We know that balancing of a chemical equation is entirely based on law of conservation of mass. However the concept of Principle of Atom Conservation (POAC) can also be related to law of conservation of mass in a chemical reaction. So, POAC can also act as a technique for balancing achemical equation. For example, for a reactionABC3 → AB + C20n applying POAC for, B & C and relating the 3 equations, we get : ( nx : number ofmoles of X) Thus, the coefficients of ABC3 , AB & C2 in the balanced chemical equation will be 2,2 & 3 respectively and the balanced chemical equation can be represented as2ABC3 → 2AB + 3C2Now answer the following questions :Q.If the atomic masses of X and Y are 10 & 30 respectivetly, then the mass of XY3 formed when 120g of Y2 reacts completely with X is : Reaction X + Y2 ¾¾® XY3a)133.3 gb)200 gc)266.6 gd)400 gCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice We know that balancing of a chemical equation is entirely based on law of conservation of mass. However the concept of Principle of Atom Conservation (POAC) can also be related to law of conservation of mass in a chemical reaction. So, POAC can also act as a technique for balancing achemical equation. For example, for a reactionABC3 → AB + C20n applying POAC for, B & C and relating the 3 equations, we get : ( nx : number ofmoles of X) Thus, the coefficients of ABC3 , AB & C2 in the balanced chemical equation will be 2,2 & 3 respectively and the balanced chemical equation can be represented as2ABC3 → 2AB + 3C2Now answer the following questions :Q.If the atomic masses of X and Y are 10 & 30 respectivetly, then the mass of XY3 formed when 120g of Y2 reacts completely with X is : Reaction X + Y2 ¾¾® XY3a)133.3 gb)200 gc)266.6 gd)400 gCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.
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