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The are (in square units) of the region bounded by x2 = 8 y , x = 4 and x-axis is
- a)2/3
- b)4/3
- c)8/3
- d)10/3
Correct answer is option 'C'. Can you explain this answer?
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The are (in square units) of the region bounded by x2 = 8 y , x = 4 an...
Given:
x² = 8y
x = 4
Finding the Area:
- Finding the Points of Intersection:
To find the points of intersection, substitute x = 4 into the equation x² = 8y:
4² = 8y
y = 2
- Calculating the Area:
The area can be calculated by taking the integral of the curve x² = 8y with respect to x, from x = 0 to x = 4:
A = ∫[0,4] (x²/8) dx
A = [x³/24] [0,4]
A = (4³/24) - (0/24)
A = 64/24
A = 8/3 square units
Therefore, the correct answer is option C, 8/3.
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The are (in square units) of the region bounded by x2 = 8 y , x = 4 and x-axis isa)2/3b)4/3c)8/3d)10/3Correct answer is option 'C'. Can you explain this answer?
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