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Radiochemical techniques can be used to determine solubility product eslimation. The measurement of radioactivity can be used to find the concentration in a solubthty equilibrium giving afak idea about  various equilibrium concentrations. In an experiment, 50.00m1 of a 0.010 81A*1103sdufion containing a silver isotope with a radioactivity of 75,000 counts per min per mi were mixed viii 100 ml of a 0.03 Na103 solution. The mixed solution was diluted 500 mi and filtered to remove al oftheAg/03predpilateleavinig behind a radioactive solution. Molar mass of AgI03 = 285 g/mol.
Q.
The remaining solution was found to have a radioactivity of 50 cane tsper min per mi. Then find the mass of the ppt of AgI03 obtained separated.
  • a)
    183 mg
  • b)
    283 mg
  • c)
    383 mg
  • d)
    483 mg
Correct answer is option 'B'. Can you explain this answer?
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Radiochemical techniques can be used to determine solubility product e...
Moles of AgIO3 precipitated = 149/150 millimoles
                         Mass of AgIO3 precipitated =285x149/150 x10-3 = 0.283 g
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Radiochemical techniques can be used to determine solubility product e...
To solve this problem, we need to apply the principles of solubility product and radioactivity measurements. Let's break down the problem into smaller steps:

1. Calculate the initial concentration of the silver isotope in the 50.00 ml solution:
- Given that the radioactivity of the solution is 75,000 counts per min per ml.
- Since the radioactivity is directly proportional to the concentration of the silver isotope, we can assume that the initial concentration of the silver isotope is also 75,000 counts per min per ml.

2. Calculate the initial number of moles of the silver isotope in the 50.00 ml solution:
- We can use the formula: Moles = Concentration x Volume.
- Moles of silver isotope = 75,000 counts/min/ml x 50.00 ml.

3. Calculate the total number of moles of silver ion in the mixed solution:
- The volume of the mixed solution is 150 ml (50 ml + 100 ml).
- The concentration of the silver ion in the mixed solution can be calculated using the formula: Concentration = Moles / Volume.
- Moles of silver ion = (75,000 counts/min/ml x 50.00 ml) / 150.00 ml.

4. Calculate the solubility product constant (Ksp) of AgI03:
- The molar mass of AgI03 is given as 285 g/mol.
- The molar ratio between Ag and AgI03 is 1:1, so the molar mass of Ag is also 285 g/mol.

5. Calculate the molar solubility of AgI03:
- The molar solubility can be calculated using the formula: Molar Solubility = Square root of (Ksp / 4).
- Since the solubility product constant (Ksp) is not given in the problem, we cannot directly calculate the molar solubility. Therefore, we need to make an assumption.

6. Assumption:
- Let's assume that the molar solubility of AgI03 is much smaller than the initial concentration of the silver ion. This assumption is reasonable since the mixed solution is diluted 500 times.

7. Calculate the moles of AgI03 precipitated:
- The moles of AgI03 precipitated can be calculated using the formula: Moles of AgI03 = Moles of silver ion - Moles of silver isotope.
- Moles of AgI03 = (75,000 counts/min/ml x 50.00 ml) / 150.00 ml - (75,000 counts/min/ml x 50.00 ml).

8. Calculate the mass of AgI03 precipitated:
- The mass of AgI03 precipitated can be calculated using the formula: Mass = Moles x Molar mass.
- Mass of AgI03 = Moles of AgI03 x 285 g/mol.

9. Calculate the final radioactivity of the remaining solution:
- The volume of the remaining solution is 500 ml.
- The concentration of the remaining silver isotope can be calculated using the formula: Concentration = Radioactivity / Volume.
- Concentration of the remaining silver isotope = 50 counts/min/ml.

10. Verify the assumption:
- Since the final
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Radiochemical techniques can be used to determine solubility product eslimation. The measurement of radioactivity can be used to find the concentration in a solubthty equilibrium giving afak idea about various equilibrium concentrations. In an experiment, 50.00m1 of a 0.010 81A*1103sdufion containing a silver isotope with a radioactivity of 75,000 counts per min per mi were mixed viii 100 ml of a 0.03 Na103 solution. The mixed solution was diluted 500 mi and filtered to remove al oftheAg/03predpilateleavinig behind a radioactive solution. Molar mass of AgI03 = 285 g/mol.Q.The remaining solution was found to have a radioactivity of 50 cane tsper min per mi. Then find the mass of the ppt of AgI03 obtained separated.a)183 mgb)283 mgc)383 mgd)483 mgCorrect answer is option 'B'. Can you explain this answer?
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Radiochemical techniques can be used to determine solubility product eslimation. The measurement of radioactivity can be used to find the concentration in a solubthty equilibrium giving afak idea about various equilibrium concentrations. In an experiment, 50.00m1 of a 0.010 81A*1103sdufion containing a silver isotope with a radioactivity of 75,000 counts per min per mi were mixed viii 100 ml of a 0.03 Na103 solution. The mixed solution was diluted 500 mi and filtered to remove al oftheAg/03predpilateleavinig behind a radioactive solution. Molar mass of AgI03 = 285 g/mol.Q.The remaining solution was found to have a radioactivity of 50 cane tsper min per mi. Then find the mass of the ppt of AgI03 obtained separated.a)183 mgb)283 mgc)383 mgd)483 mgCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Radiochemical techniques can be used to determine solubility product eslimation. The measurement of radioactivity can be used to find the concentration in a solubthty equilibrium giving afak idea about various equilibrium concentrations. In an experiment, 50.00m1 of a 0.010 81A*1103sdufion containing a silver isotope with a radioactivity of 75,000 counts per min per mi were mixed viii 100 ml of a 0.03 Na103 solution. The mixed solution was diluted 500 mi and filtered to remove al oftheAg/03predpilateleavinig behind a radioactive solution. Molar mass of AgI03 = 285 g/mol.Q.The remaining solution was found to have a radioactivity of 50 cane tsper min per mi. Then find the mass of the ppt of AgI03 obtained separated.a)183 mgb)283 mgc)383 mgd)483 mgCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Radiochemical techniques can be used to determine solubility product eslimation. The measurement of radioactivity can be used to find the concentration in a solubthty equilibrium giving afak idea about various equilibrium concentrations. In an experiment, 50.00m1 of a 0.010 81A*1103sdufion containing a silver isotope with a radioactivity of 75,000 counts per min per mi were mixed viii 100 ml of a 0.03 Na103 solution. The mixed solution was diluted 500 mi and filtered to remove al oftheAg/03predpilateleavinig behind a radioactive solution. Molar mass of AgI03 = 285 g/mol.Q.The remaining solution was found to have a radioactivity of 50 cane tsper min per mi. Then find the mass of the ppt of AgI03 obtained separated.a)183 mgb)283 mgc)383 mgd)483 mgCorrect answer is option 'B'. Can you explain this answer?.
Solutions for Radiochemical techniques can be used to determine solubility product eslimation. The measurement of radioactivity can be used to find the concentration in a solubthty equilibrium giving afak idea about various equilibrium concentrations. In an experiment, 50.00m1 of a 0.010 81A*1103sdufion containing a silver isotope with a radioactivity of 75,000 counts per min per mi were mixed viii 100 ml of a 0.03 Na103 solution. The mixed solution was diluted 500 mi and filtered to remove al oftheAg/03predpilateleavinig behind a radioactive solution. Molar mass of AgI03 = 285 g/mol.Q.The remaining solution was found to have a radioactivity of 50 cane tsper min per mi. Then find the mass of the ppt of AgI03 obtained separated.a)183 mgb)283 mgc)383 mgd)483 mgCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of Radiochemical techniques can be used to determine solubility product eslimation. The measurement of radioactivity can be used to find the concentration in a solubthty equilibrium giving afak idea about various equilibrium concentrations. In an experiment, 50.00m1 of a 0.010 81A*1103sdufion containing a silver isotope with a radioactivity of 75,000 counts per min per mi were mixed viii 100 ml of a 0.03 Na103 solution. The mixed solution was diluted 500 mi and filtered to remove al oftheAg/03predpilateleavinig behind a radioactive solution. Molar mass of AgI03 = 285 g/mol.Q.The remaining solution was found to have a radioactivity of 50 cane tsper min per mi. Then find the mass of the ppt of AgI03 obtained separated.a)183 mgb)283 mgc)383 mgd)483 mgCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Radiochemical techniques can be used to determine solubility product eslimation. The measurement of radioactivity can be used to find the concentration in a solubthty equilibrium giving afak idea about various equilibrium concentrations. In an experiment, 50.00m1 of a 0.010 81A*1103sdufion containing a silver isotope with a radioactivity of 75,000 counts per min per mi were mixed viii 100 ml of a 0.03 Na103 solution. The mixed solution was diluted 500 mi and filtered to remove al oftheAg/03predpilateleavinig behind a radioactive solution. Molar mass of AgI03 = 285 g/mol.Q.The remaining solution was found to have a radioactivity of 50 cane tsper min per mi. Then find the mass of the ppt of AgI03 obtained separated.a)183 mgb)283 mgc)383 mgd)483 mgCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for Radiochemical techniques can be used to determine solubility product eslimation. The measurement of radioactivity can be used to find the concentration in a solubthty equilibrium giving afak idea about various equilibrium concentrations. In an experiment, 50.00m1 of a 0.010 81A*1103sdufion containing a silver isotope with a radioactivity of 75,000 counts per min per mi were mixed viii 100 ml of a 0.03 Na103 solution. The mixed solution was diluted 500 mi and filtered to remove al oftheAg/03predpilateleavinig behind a radioactive solution. Molar mass of AgI03 = 285 g/mol.Q.The remaining solution was found to have a radioactivity of 50 cane tsper min per mi. Then find the mass of the ppt of AgI03 obtained separated.a)183 mgb)283 mgc)383 mgd)483 mgCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of Radiochemical techniques can be used to determine solubility product eslimation. The measurement of radioactivity can be used to find the concentration in a solubthty equilibrium giving afak idea about various equilibrium concentrations. In an experiment, 50.00m1 of a 0.010 81A*1103sdufion containing a silver isotope with a radioactivity of 75,000 counts per min per mi were mixed viii 100 ml of a 0.03 Na103 solution. The mixed solution was diluted 500 mi and filtered to remove al oftheAg/03predpilateleavinig behind a radioactive solution. Molar mass of AgI03 = 285 g/mol.Q.The remaining solution was found to have a radioactivity of 50 cane tsper min per mi. Then find the mass of the ppt of AgI03 obtained separated.a)183 mgb)283 mgc)383 mgd)483 mgCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Radiochemical techniques can be used to determine solubility product eslimation. The measurement of radioactivity can be used to find the concentration in a solubthty equilibrium giving afak idea about various equilibrium concentrations. In an experiment, 50.00m1 of a 0.010 81A*1103sdufion containing a silver isotope with a radioactivity of 75,000 counts per min per mi were mixed viii 100 ml of a 0.03 Na103 solution. The mixed solution was diluted 500 mi and filtered to remove al oftheAg/03predpilateleavinig behind a radioactive solution. Molar mass of AgI03 = 285 g/mol.Q.The remaining solution was found to have a radioactivity of 50 cane tsper min per mi. Then find the mass of the ppt of AgI03 obtained separated.a)183 mgb)283 mgc)383 mgd)483 mgCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice JEE tests.
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